如何在Windows批處理文件中拆分字符串？

Question

我想分裂並在Windows批處理文件中創建一個新的字符串，但我無法弄清楚如何做到這一點。

我試圖將此轉換：

Crysis3_2560x1440 

要這樣：

Crysis 3 - 2560x1440 

然後：

HD7970CrossFire 

要這樣：

HD 7970 CrossFire 

有什麼建議嗎？

Answer 1

編輯：這是管理的意見中提到的特殊情況下，新版本：

@echo off 
setlocal EnableDelayedExpansion 

for /F %%a in (inputFile.txt) do (
    set string=%%a 
    echo Original: !string! 
    call :Splint string 
    echo Modified: !string! 
) 
goto :EOF 

:Splint string 
set string=!%1! 
rem Change underscore by space-dash-space 
set string=%string:_= - % 
rem Separate the string at first group of digits or space 
for /F "tokens=1* delims=" %%a in ("%string%") do (
    set first=%%a 
    set last=%%b 
) 
rem Eliminate first part from middle 
set middle=!string:%first%=! 
rem Eliminate last part from middle, if exists 
if defined last set middle=!middle:%last%=! 
rem Eliminate spaces from middle 
set middle=%middle: =% 
rem Assemble the result 
if defined middle (
    set %1=%first% %middle% %last% 
) else (
    set %1=%first% %last% 
) 
exit /B 

輸出：

Original: Crysis3_2560x1440 
Modified: Crysis 3 - 2560x1440 
Original: HD7970CrossFire 
Modified: HD 7970 CrossFire 
Original: Skyrim_2560x1440 
Modified: Skyrim - 2560x1440 
Original: SleepingDogs_2560x1440 
Modified: SleepingDogs - 2560x1440 
Original: GTX680 
Modified: GTX 680 

安東尼

Answer 2

你可以使用這些片段作爲基地...

set in=Crysis3_2560x1440 
set out=!in:_= - ! 
set in 
set out 

而且......

set in=HD7970CrossFire 
set out=!in:HD7970CrossFire=HD 7970 CrossFire! 
set in 
set out 

雖然我只是不明白爲什麼你不只是去

set str=HD 7970 CrossFire