蟒蛇比較的元組和字典

Question

我要比較兩個組，並找到在蟒蛇的區別：

>>> mysql_orders = ((50434L, 5901L), (50733L, 5901L)) 
>>> opera_orders = [{'orderId': 'WEB050434', 'accountId': '00T001'}, {'orderId': 'WEB050733', 'accountId': '00T001'}, {'orderId': 'DOC075185', 'accountId': '00T001'}, {'orderId': 'WEB081859', 'accountId': '00T001'}] 

一個是元組列表和字典其中列表中的第一個項目可能是另外一個列表沒有WEB/DOC前綴的orederId。

找不到mysql_orders列表中缺失的orderId的正確方法是什麼？

Answer 1

使用正則表達式去除字母，但前提是數字總是晚一些，

import re 

mysql_orders = ((50434L, 5901L), (50733L, 5901L)) 

opera_orders = [{'orderId': 'WEB050434', 'accountId': '00T001'}, {'orderId': 'WEB050733', 'accountId': '00T001'}, {'orderId': 'DOC075185', 'accountId': '00T001'}, {'orderId': 'WEB081859', 'accountId': '00T001'}] 

mysql_orders = [element for tupl in mysql_orders for element in tupl] 

missing_order_ids = [opera_order['orderId'] for opera_order in opera_orders if long(re.split('\D+', opera_order['orderId'])[1]) not in mysql_orders] 

print missing_order_ids 

Answer 2

如果信件可能會或可能不會有，但領先的0是永遠存在的，你可以用一組帶：

from string import ascii_letters 

st = set(str(a) for a,_ in mysql_orders) 

missing = [d['orderId'] for d in opera_orders if not d['orderId'].strip(ascii_letters)[1:] in st] 

print(missing) 

['DOC075185', 'WEB081859'] 

如果前綴是永遠存在的只是切片：

missing = [d['orderId'] for d in opera_orders if not d['orderId'][4:] in st]