2017-04-14 276 views
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5.Consider以下庫架構數據庫關係代數,SQL查詢

Books (book_no,title,authors,publisher) 
Borrower(borrower_id, name, DOB, job) 
Borrowed(borrower_id,book_no,date) 

寫關係代數

  • 一個下列查詢。查找借用「Wiley」發佈的3本以上書籍的借款人的姓名和借閱人ID
  • b。查找借用「wiley」
  • 發佈的任何書的借用人的姓名c。找到每個借款人借入的書籍的平均數量。
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你到目前爲止嘗試過什麼? – Rams

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你有什麼問題?你到目前爲止嘗試了什麼? –

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a。你需要加入表格並按照操作進行分組,並給出條件Wiley,b。通過加入所需的表格簡單地給出條件,c。與'a'相同,但不需要條件,只需要計數 – Rams

回答

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按你的問題,SQL查詢是這樣

問題1

select B.borrower_id, B.name 
    from Borrower as B, Borrowed as Bw, Books as Bk 
where B.borrower_id = Bw.borrower_id 
    and Bw.book_no = Bk.book_no 
    and Bk.publisher = 'Wiley' 
group by B.borrower_id, B.name 
having count(Bw.borrower_id) > 3 

問題2

select B.name 
    from Borrower as B, Borrowed as Bw, Books as Bk 
where B.borrower_id = Bw.borrower_id 
    and Bw.book_no = Bk.book_no 
    and Bk.publisher = 'Wiley' 
    group by B.name 

問題3

select B.borrower_id, B.name, count(Bw.borrower_id) as cnt 
    from Borrower as B, Borrowed as Bw, Books as Bk 
where B.borrower_id = Bw.borrower_id 
    and Bw.book_no = Bk.book_no 
group by B.borrower_id, B.name 
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對不起,這不是關係代數... –

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@GiorgosAltanis更新請檢查 – ITSGuru

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這仍然是SQL&沒有任何常見的關係代數變體。 – philipxy