Twitter4j AccesToken與JavaFX瀏覽器

我想認證用戶使用嵌入式瀏覽器與javafx。我可以獲取Twitter提供給我的PIN（字符串），但是當我嘗試創建AccesToken時，它無法正確創建。（我不能得到我的令牌或tokenSecret，都爲空）。Twitter4j AccesToken與JavaFX瀏覽器

這裏是我的代碼：

public static void main(String[] args) 
    { 
    Application.launch(args); 
    } 

@Override 
public void start(Stage primaryStage) throws Exception 
    { 
    primaryStage.setTitle("WebView test"); 

    WebView browser = new WebView(); 

    engine = browser.getEngine(); 

    twitter = new TwitterFactory().getInstance(); 
    twitter.setOAuthConsumer(CONSUMER_KEY, CONSUMER_SECRET); 

    requestToken = twitter.getOAuthRequestToken(); 

    String url = requestToken.getAuthorizationURL(); 


    engine.load(url); 

    engine.getLoadWorker().stateProperty().addListener(new ChangeListener<State>() 
     { 

      public void changed(ObservableValue ov, State oldState, State newState) 
       { 
       if (newState==State.SUCCEEDED && engine.getLocation().equals("https://api.twitter.com/oauth/authorize")) 
        { 
        String pin = engine.getDocument().getDocumentElement().getElementsByTagName("code").item(0).getTextContent(); 
        printAccesToken(pin); 
        } 
       } 

     }); 

    StackPane sp = new StackPane(); 
    sp.getChildren().add(browser); 

    Scene root = new Scene(sp); 

    primaryStage.setScene(root); 
    primaryStage.show(); 
    } 



private void printAccesToken(String pin) 
    { 
    AccessToken accessToken = null; 

    try 
     { 
     accessToken = twitter.getOAuthAccessToken(requestToken, pin); 
     } 
    catch (TwitterException e) 
     { 
     e.printStackTrace(); 
     } 
    System.out.println(accessToken.getToken()); 

    } 

/*------------------------------------------------------------------*\ 
|*       Attributs Private      *| 
\*------------------------------------------------------------------*/ 
private WebEngine engine; 
private Twitter twitter; 
private RequestToken requestToken; 
private static final String CONSUMER_KEY = "xxx"; 
private static final String CONSUMER_SECRET = "xxx";

我根據自己對twitter4j提供了代碼示例，據我可以告訴我做同樣的事情，只有我得到的字符串不是通過鍵盤inputed我把它直接從瀏覽器...

http://twitter4j.org/en/code-examples.html

基於自己對例7

來源

2012-09-04 Tibor Udvari