我想通過json從ajax調用中獲取數據,並在成功調用ajax後訪問數據。爲此目的,我寫了下面的代碼:在從MySQL獲取數據時在json中獲取額外的值
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
require_once('../include/functions.php');
// session_start();
if(isset($_POST['bike_id']))
{
$rows = array();
// echo " I am in isset";
$bike_id = $_POST['bike_id'];
// $modal_name = $_POST['modal_name'];
// $json['insertModal'] = false;
// json_decode($modal_name);
json_decode($bike_id);
$result = selectBike_Modal($bike_id);
while ($row = mysqli_fetch_array($result))
{
$rows[] = $row;
}
echo json_encode($rows);
}
else
{
echo "bike_id is not set";
}
?>
現在我想通過javascript來訪問它:
$('#choose_bike').on('blur',
function (e) {
e.preventDefault();
var bike_id = $('#choose_bike').val();
// var modal_name = $('#modal_name').val();
// // alert("bike_id is " + bike_id);
alert("On blur is clicked.");
if (bike_id == "Select A Bike")
{
$('#defaultError').addClass("alert alert-danger");
$('#defaultError').text("Please choose a Bike");
}
else
{
// alert("Bike is : " + bike_id);
$.ajax(
{
url:'../admin/backend/getModal.php',
type:'POST',
data: { bike_id: bike_id},
dataType:"json",
success:function(data)
{
alert(" i am in success");
var obj = JSON.parse(data);
alert("object is " +obj);
},
error : function() { console.log(arguments); }
}
);
}
});
我有兩個問題:
,我沒有得到任何東西后:
警報(「我在成功」);
指下不工作:
var obj = JSON.parse(data);
alert("object is " +obj);
- PHP的響應如下:
[{"0":"5","bike_modal_id":"5","1":"shahjahan","bike_modal_name":"shahjahan","2":"30","bike_id":"30"},{"0":"6","bike_modal_id":"6","1":"ram","bike_modal_name":"ram","2":"30","bike_id":"30"}]
我正在
"0":"5","bike_modal_id":"5"
額外。 請幫我解析JavaScript中的json,並只獲取所需的ajax值。
編輯:
選擇bike_model樣子:
function selectBike_Modal($bike_id)
{
include("connectvars.php");
$query = "select * from bike_model where bike_id = '$bike_id'";
$result = mysqli_query($dbc,$query)
or die('error in fetching');
// if (mysqli_num_rows($result))
// return 0;
// else
return $result;
// if (())
// {
// return $result;
// }
// else
// {
// return 0;
// }
}
能否請您分享了'selectBike_Modal()' –
您是否獲得在瀏覽器的Web控制檯的任何錯誤代碼在開發人員工具? –
yes,** Uncaught語法錯誤:意外的令牌o ** –