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我正在開發iphone應用程序,我有標籤的電話號碼,我需要撥打電話號碼從用戶觸摸。我嘗試了下面的代碼,但沒有打電話,我目前正在使用xcode模擬器進行檢查。通過編程從iphone應用程序撥打電話
我的代碼,
在我的頭文件
IBOutlet UILabel* lableMakeCall1;
@property(nonatomic,retain) UIView* lableMakeCall1;
我的.m文件包含
- (void)viewDidLoad
{
lableMakeCall1.userInteractionEnabled = YES;
UITapGestureRecognizer *tapGesture1 = \
[[UITapGestureRecognizer alloc]
initWithTarget:self action:@selector(didTapLabelWithGesture1:)];
[lableMakeCall1 addGestureRecognizer:tapGesture1];
}
- (void)didTapLabelWithGesture1:(UITapGestureRecognizer *)tapGesture1 {
NSString *phoneNumber = [@"tel://" stringByAppendingString:lableMakeCall1.text];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];
/*
I tried in this code also
NSString *phoneNumber = [@"telprompt://" stringByAppendingString:lableMakeCall1.text];
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:phoneNumber]];*/
}
另外,[spec說](https://developer.apple.com/library/ios/featuredarticles/iPhoneURLScheme_Reference/PhoneLinks/PhoneLinks.html#//apple_ref/doc/uid/TP40007899-CH6-SW1)你使用'tel:',即沒有雙斜槓,但你必須在手機上測試,或者如果你使用'facetime:'鏈接,那麼你可以測試ann ipod/ipad –
Petesh
2014-10-01 15:42:32
還要確保有電話號碼中沒有空格。 – rmaddy 2014-10-01 16:03:03