2010-05-11 52 views
1

上傳的文件我有一個服務器上的文件上傳此代碼:如何讀取從XAMPP

<tr> 
<td> 
<form enctype="multipart/form-data" action="uploadaction.php" method="POST"> 
<input type="hidden" name="MAX_FILE_SIZE" value="100000" /> 
</td> 
</tr> 
<tr> 
<td> 
Select the image: <input name="uploadedfile" type="file" /> 

</td> 
<tr> 
<td> 
<input type="submit" value="Upload File" /> 
</form> 
</td> 
</tr> 

而這裏的操作形式:

<?php 
$target_path = "uploads/"; 

$target_path = $target_path . basename($_FILES['uploadedfile']['name']); 

if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) { 
    echo "The file ". basename($_FILES['uploadedfile']['name']). 
    " has been uploaded"; 
} else{ 
    echo "There was an error uploading the file, please try again!"; 
} 
?> 

我會用什麼PHP函數? 你能給我一個關於如何讀取文件並將其顯示在瀏覽器中的例子嗎? 請幫忙,謝謝。

+0

*(參考)* http://de.php.net/manual/en/features.file-upload.php – Gordon 2010-05-11 11:14:43

+1

如果文件上傳成功,它應該位於您發送給它的目錄中。從那裏你如何選擇顯示它的種類取決於文件是什麼。 – 2010-05-11 20:22:00

+0

它是一個圖像文件,我如何從瀏覽器中查看它? – user225269 2010-05-12 02:32:45

回答