Python庫函數問題

Question

我有一個文本文件名爲「movies.txt」那裏面是那些臺詞：

The_Godfather Francis_Ford_Coppola Crime 1972 
The_Dark_Knight Christofer_Nolan Action 2008 
Pulp_Fiction Quentin_Tarantino Drama 1994 

從文件我想提取這些行，並與其他功能（按年份搜索使用它們/ genere ect）。 要打開我使用的文件：

f=open("movies.txt","r") 
s=f.read() 
print(s) 
f.close() 

但似乎我缺少的東西，這裏是代碼的樣本：

f=open("movies.txt","r") 
s=f.read() 
print(s) 
f.close() 

def search_movie_by_name(name,path): 
    mystring = path 
    for i in path: 
     if word in mystring: 
      print("Found") 

它是什麼做的代碼？或者我如何打開它？

Answer 1

所以你的代碼沒有多大意義。未聲明的變量，未使用的文件內容等，我相信你想要做的就是打開文件，並通過行這樣的迭代：

def search_movie_by_name(name, path): 
    with open(path, 'r') as f: 
     for line in f.readlines(): 
      if name in line: 
       print("Found") 
       return line 

例子：

In [10]: def search_movie_by_name(name, path): 
    ...:  with open(path, 'r') as f: 
    ...:   for line in f.readlines(): 
    ...:    if name in line: 
    ...:     print("Found") 
    ...:     return 
    ...: 

In [11]: search_movie_by_name("Godfather", "movies.txt") 
Found 

它打開該文件在給出path並遍歷這些行，直到找到給定的行name並打印「找到」。

在有限的修改代碼：

f=open("movies.txt","r") 
s=f.read() 
print(s) 
f.close() 

def search_movie_by_name(name, file_content): 
    for line in file_content.splitlines(): 
     if name in line: 
      print("Found") 

例子：

In [18]: f=open("movies.txt","r") 
    ...: s=f.read() 
    ...: print(s) 
    ...: f.close() 
    ...: 
    ...: def search_movie_by_name(name,file_content): 
    ...:  for line in file_content.splitlines(): 
    ...:   if name in line: 
    ...:    print("Found") 
    ...:    

The_Godfather Francis_Ford_Coppola Crime 1972 
The_Dark_Knight Christofer_Nolan Action 2008 
Pulp_Fiction Quentin_Tarantino Drama 1994 


In [19]: search_movie_by_name("Godfather", s) 
Found