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我想用Play發送文件到Stripe!斯卡拉2.5。
該文件說,應該將請求(捲曲當量)是這樣的:使用Play將文檔發送到Stripe! Scala 2.5
curl https://uploads.stripe.com/v1/files \
-u sk_test_BQokikJOvBiI2HlWgH4olfQ2: \
-F purpose=dispute_evidence \
-F file="@/path/to/a/file.jpg"
我的是:
def test: Action[MultipartFormData[TemporaryFile]] = Action(parse.multipartFormData) { request =>
val image = request.body.file("picture").get
val info = Map("purpose" -> Seq("identity_document"))
val attachment =
FilePart[TemporaryFile](
key = "file",
filename = "file",
contentType = image.contentType,
ref = image.ref)
val formData: MultipartFormData[TemporaryFile] =
MultipartFormData(
dataParts = info,
files = Seq(attachment),
badParts = Seq.empty)
import services.MultipartFormDataWritable.anyContentAsMultipartFormWritable
wSClient
.url("https://uploads.stripe.com/v1/files")
.withAuth("secret_key", "", WSAuthScheme.BASIC)
.post(formData)
.map(response => println(response.body))
Ok
}
但條紋返回我這個Bad Request error
:
"error": {
"type": "invalid_request_error",
"message": "Missing required param: file.",
"param": "file"
}
什麼時我做錯了?