2013-07-22 110 views
0

我一直在試用我的PHP技巧,看起來當我嘗試從我的Android應用程序向PHP發送信息時,它似乎只發送參數名稱(數據庫顯示:作爲例如。)輸出到數據庫。我們使用PDO作爲與MySQL數據庫通信的方式。參數問題

這裏是編碼如下:

$query = "INSERT INTO Customer (Lname, Fname, Address, City, State, ZIP, Phone, myusername, mypassword) VALUES (':Lname', ':Fname', ':Address', ':City', ':State', ':ZIP', ':Phone', ':myusername', ':mypassword')"; 

//Again, we need to update our tokens with the actual data: 
$query_params = array(
    ':Lname' => $_POST['LName'], 
    ':Fname' => $_POST['FName'], 
    ':Address' => $_POST['Address'], 
    ':City' => $_POST['City'], 
    ':State' => $_POST['State'], 
    ':ZIP' => $_POST['ZIP'], 
    ':Phone' => $_POST['Phone'], 
      ':myusername' => $_POST['username'], 
      ':mypassword' => $_POST['password'] 
); 

//time to run our query, and create the user 
try { 
    $stmt = $db->prepare($query); 
    $result = $stmt->execute($query_params); 
} 
catch (PDOException $ex) { 
    // For testing, you could use a die and message. 
    //die("Failed to run query: " . $ex->getMessage()); 

    //or just use this use this one: 
    $response["success"] = 0; 
    $response["message"] = $ex->getMessage(); 
    die(json_encode($response)); 
} 

回答

1

已包含在您的查詢字符串文字值。

$query = "INSERT INTO Customer (Lname, Fname, Address, City, State, ZIP, Phone, myusername, mypassword) 
VALUES (':Lname', ':Fname', ':Address', ':City', ':State', ':ZIP', ':Phone', ':myusername', ':mypassword')"; 

應該

$query = "INSERT INTO Customer (Lname, Fname, Address, City, State, ZIP, Phone, myusername, mypassword) 
VALUES (:Lname, :Fname, :Address, :City, :State, :ZIP, :Phone, :myusername, :mypassword)"; 
0

您需要從您的SQL值刪除引號,因爲它被解釋爲文字字符串。如果你刪除它們,你應該都很好:)

$query = "INSERT INTO Customer (Lname, Fname, Address, City, State, ZIP, Phone, myusername, mypassword) VALUES (':Lname', ':Fname', ':Address', ':City', ':State', ':ZIP', ':Phone', ':myusername', ':mypassword')";