在Mongoose中更新非常嵌套的文檔

Question

如何根據以下Schema更新array1.array2.status？

var SomeSchema = new mongoose.Schema({ 
    status: Boolean, 
    array1: [{ 
     array2[{ 
      status: boolean 
     }] 
    }] 
}) 

Answer 1

首先，這將是很好重新組織架構成子模式是這樣的：

var valueItemSchema = new mongoose.Schema({ 
    _id: Number, 
    status: Boolean 
}); 

var subItemSchema = new mongoose.Schema({ 
    _id: Number, 
    array2: [valueItemSchema] 
}); 

/* 
//or this if you dont want _id in your nested documents 

var valueItemSchema = new mongoose.Schema({ 
    status: Boolean 
}, { 
    _id: false 
}); 

var subItemSchema = new mongoose.Schema({ 
    array2: [valueItemSchema] 
}, { 
    _id: false 
}); 
*/ 

var itemSchema = new mongoose.Schema({ 
    status: Boolean, 
    array1: [subItemSchema] 
}); 

var valueItem = db.model('ValueItem', valueItemSchema); 
var SubItem = db.model('SubItem', subItemSchema); 
var Item = db.model('Item', itemSchema); 

//create a new item 
var myItem = new Item({ 
    status: true, 
    array1: new SubItem({ 
     _id: 0, 
     array2: [new valueItem({ 
      _id: 0, 
      "status": true 
     }), new valueItem({ 
      _id: 1, 
      "status": false 
     }), new valueItem({ 
      _id: 2, 
      "status": true 
     })] 
    }) 
}); 

然後，您可以更新array2通過_id的元素：

Item.findOne({ 
    status: true 
}).exec(
    function(err, result) { 
     result.array1.id(0).array2.id(0).status=false; 
     result.save(function(err) { 
      console.log(result) 
     }); 
    } 
); 

或者如果您不想在索引中更新_id，請按索引更新：

Item.findOne({ 
    status: true 
}).exec(
    function(err, result) { 

     result.array1[0].array2[0].status=false; 
     result.save(function(err) { 
      console.log(result) 
     }); 
    } 
); 

Here是一個完整的演示