兩字組櫃檯幾乎完整的Python

Question

我有一個幾乎功能兩字櫃檯，但我堅持兩點：

一）打印鍵和值正確地爲我的關鍵是循環的代碼到一個元組

B）接受輸入的新線

到目前爲止我有：

bigrams = {} 

line = input ('Line: ').split() 
while len(line) > 1:      
    bigram_key = tuple(line[0:2])  
    if bigram_key not in bigrams:  
    bigrams[bigram_key] = 1   
    else:        
    bigrams[bigram_key] += 1   
    line = line[1:]      

for entry in bigrams.keys(): 
    print (entry,":",bigrams[entry]) 

輸入單行其中一期工程，雖然打印額外格賓斯（技術術語），我不想：

Line: The Big The Big Red Fox 
('Big', 'The') : 1 
('Big', 'Red') : 1 
('Red', 'Fox') : 1 
('The', 'Big') : 2 

當我後：

Line: The Big The Big Red Fox 
Big The: 1 
Big Red: 1 
Red Fox: 1 
The Big: 2 

然後，我需要用它來輸入多行的工作！

Answer 1

對於你的第一個問題：

>>> for i in bigrams: 
...  print ' '.join(i),':',bigrams[i] 
... 
Big The : 1 
Red Fox : 1 
Big Red : 1 
The Big : 2 

對於你的第二個問題：

>>> bigrams={} 
>>> while True: 
...  print "Enter some text or enter `break` keyword to stop:" 
...  line = raw_input() 
...  if line.lower() == 'break': break 
...  line = line.split() 
...  for i,j in zip(line[:-1],line[1:]): # Keep taking two consecutive words (bigrams) until end of line 
...   bigrams.setdefault((i,j),0) 
...   bigrams[(i,j)]+=1 

Answer 2

這是我公司生產的最終代碼。感謝您的支持！

bigrams = {} 
while True: 
    line = input ('Line: ').lower().split() 
    while len(line) > 1:      
    bigram_key = tuple(line[0:2])  
    if bigram_key not in bigrams:  
     bigrams[bigram_key] = 1   
    else:        
     bigrams[bigram_key] += 1   
    line = line[1:] 
    if line == []: 
    break 
for entry in bigrams: 
    if bigrams[entry] > 1: 
    print(' '.join(entry)+':',bigrams[entry])