在Ruby中，如何根據鍵中的單詞數量對散列中的元素進行排序？

Question

例如：

{"job" => 1, "big job" => 2, "super job" => 1, "work" => 2, "super big job" => 1} 

我想變成像這樣

{"super big job" => 1, "big job" => 2, "super job" => 1, "job" => 1, , "work" => 2} 

即三個詞鍵先走，然後雙字鍵，一個字鍵走過去。 我知道我可以使用key.split（''）.length函數來計算單詞，但我怎樣才能使用它來實際修改哈希中元素的順序。

Answer 1

你可以做這樣的事情：

a = {"job" => 1, "big job" => 2, "super job" => 1, "work" => 2, "super big job" => 1} 
Hash[a.sort_by { |k, v| k.split.size }.reverse] 
# => {"super big job"=>1, "super job"=>1, "big job"=>2, "work"=>2, "job"=>1} 

Answer 2

x = {"job" => 1, "big job" => 2, "super job" => 1, "work" => 2, "super big job" => 1} 

p x.sort_by{|x,|-x.split.size}.to_h #=> {"super big job"=>1, "big job"=>2, "super job"=>1, "work"=>2, "job"=>1}