Question

我想用SQL_CALC_FOUND_ROWS和MYSQLI來計算我的表上的訪問者，但它很慢。它超過15秒。我能做些什麼使它更快？ 我不得不提到我的表是MyISAM，總共有超過200萬行。

if ($result = $mysqli->query("SELECT SQL_CALC_FOUND_ROWS * FROM visitors_table WHERE visitor_affiliate= 'first user'")) { 
    /* determine number of rows result set */ 

    $row_cnt = $result->num_rows; 

    printf("Result set has %d rows.\n", $row_cnt); 

    /* close result set */ 
    $result->close(); 
} 


if ($result2 = $mysqli->query("SELECT SQL_CALC_FOUND_ROWS * FROM visitors_table WHERE visitor_affiliate= 'seconduser'")) { 
     /* determine number of rows result set */ 

     $row_cnt2 = $result2->num_rows; 

     printf("Result set has %d rows.\n", $row_cnt2); 

     /* close result set */ 
     $result2->close(); 
    } 

if ($result3 = $mysqli->query("SELECT SQL_CALC_FOUND_ROWS * FROM visitors_table WHERE visitor_affiliate= 'thirduser'")) { 
     /* determine number of rows result set */ 

     $row_cnt3 = $result3->num_rows; 

     printf("Result set has %d rows.\n", $row_cnt3); 

     /* close result set */ 
     $result2->close(); 
    } 

任何幫助表示讚賞.. 提前感謝！

Answer 1

確保您使用的列上visitor_affiliate索引：

CREATE INDEX aff_index ON visitors_table(visitor_affiliate) ; 

然後，你需要一個查詢來獲得三種結果：

SELECT visitor_affiliate, COUNT(*) AS tot FROM visitors_table 
WHERE visitor_affiliate IN ('firstuser', 'seconduser', 'thirduser') 
GROUP BY visitor_affiliate 

它通常比三個查詢更快的。

如果您仍然需要分開查詢：

SELECT COUNT(*) AS tot FROM visitors_table 
WHERE visitor_affiliate IN = 'firstuser'