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我有我自己的類和operator =的問題。當我試圖將一個類的一個對象歸入類Cow的另一個類之外時,我得到一個信息「這個聲明在C++中沒有存儲類或類型說明符」。有什麼問題?我很抱歉我的英語。「此聲明在C++中沒有存儲類或類型說明符」
#include "Header.h"
Cow cow5;
Cow cow6;
cow5 = cow6;
int main()
{
Cow cow1;
Cow cow2("cowa22", "hobby", 8);
Cow cow3 = cow2;
Cow cow4;
cow2.operator=(cow3);
}
#include "Header.h"
#include <string>
#include <iostream>
Cow::Cow()
{
strcpy_s(name, sizeof(char)*20, "unnamed");
hobby = nullptr;
weight = 0;
}
Cow::Cow(const char * nm, const char * ho, double wt)
{
strcpy_s(name, sizeof(char) * 20, nm);
hobby = new char[strlen(ho) + 1];
strcpy_s(hobby, sizeof(char)*(strlen(ho)+1), ho);
weight = wt;
}
Cow::Cow(const Cow & c)
{
strcpy_s(name, sizeof(char) * 20, c.name);
hobby = new char[strlen(c.hobby) + 1];
strcpy_s(hobby, sizeof(char)*(strlen(c.hobby) + 1), c.hobby);
weight = c.weight;
}
Cow::~Cow()
{
delete[] hobby;
}
Cow & Cow::operator=(const Cow & c)
{
if (&c == this)
return *this;
delete[] hobby;
strcpy_s(name, sizeof(char) * 20, c.name);
hobby = new char[strlen(c.hobby) + 1];
strcpy_s(hobby, sizeof(char)*(strlen(c.hobby) + 1), c.hobby);
weight = c.weight;
return *this;
}
void Cow::ShowCow() const
{
std::cout << "Name: " << name << std::endl
<< "Hobby: " << hobby << std::endl
<< "Weight: " << weight << std::endl;
}
您粘貼.cpp兩次而不是.h和.cpp – Borgleader
只是一個文體評論。不要在C++中使用char數組,它使用'strcpy_s'指示,而是使用'std :: string'。 –