解析JSON jQuery的

Question

我的要求阿賈克斯與json_encode：

[{"idHome":"1","Photo":"home-1.jpg","Publier":"1"}, 
{"idHome":"2","Photo":"home2.jpg","Publier":"1"}, 
{"idHome":"3","Photo":"home3.jpg","Publier":"1"}] 

var string = JSON.stringify(data); 

var obj = $.parseJSON(string); 

console.log(string); 

var idHome = obj.idHome; 

var photo = obj.Photo; 


console.log(obj.idHome); 

console.log(obj.Photo); 

問題的解析JSON

控制檯日誌：

[{"idHome":"1","Photo":"home-1.jpg","Publier":"1"},{"idHome":"2","Photo":"home-2.jpg","Publier":"1"},{"idHome":"3","Photo":"home-3.jpg","Publier":"1"}] 

undefined 

undefined 

Answer 1

這是一個數組，所以你需要通過，有這麼多的方法來做到這循環。

for (i = 0; i < obj.length; i++) { 
    console.log(obj[i].idHome); 
    console.log(obj[i].Photo); 
} 

或：

obj.forEach(function(val) { 
    console.log(val.idHome); 
    console.log(val.Photo); 
}); 

或：

for (var i in obj) { 
    console.log(obj[i].idHome); 
    console.log(obj[i].Photo); 
} 

Jquery的用途：

$.each(obj, function(_, val){ 
    console.log(val.idHome); 
    console.log(val.Photo); 
}); 

等....

Answer 2

你JSON是三個對象的數組。

嘗試

console.log(obj[0].idHome); 
console.log(obj[0].Photo); 

更多信息： http://www.w3schools.com/json/json_syntax.asp