的GreaseMonkey腳本，而不是解析鏈接添加到DOM

Question

我使用的Greasemonkey腳本，即與YouTube已有：http://userscripts.org/scripts/review/47198

這個腳本旨在強調已經訪問過的鏈接。關鍵的因素是去除使參數無效的url參數。

i.e.: http://www.youtube.com/watch?v=aKWPht3fU-o    != 
     http://www.youtube.com/watch?v=aKWPht3fU-o&featured=fvw 

最重要的部分是：

var cleanlink, dirtylink, i, x, aXpath; 
aXpath = new Array(7); 
aXpath[0] = '//a[contains(@href, "feature=related")]'; 
aXpath[1] = '//a[contains(@href, "feature=relmfu")]'; 
aXpath[2] = '//a[contains(@href, "feature=g-")]'; 
aXpath[3] = '//a[contains(@href, "feature=b-")]'; // &feature=b- all browse 
aXpath[4] = '//a[contains(@href, "/user/")]'; 
aXpath[5] = '//a[contains(@href, "/videos")]'; // search 
aXpath[6] = '//a[contains(@href, "&list")]';  // playlists 

for(x in aXpath) { 
    dirtylink = document.evaluate(aXpath[x], document, null, XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE, null); 
    for (i = 0; i < dirtylink.snapshotLength; i++) { 
     cleanlink = dirtylink.snapshotItem(i); 
     switch (x){ 
     case 6: 
        cleanlink.href = cleanlink.href.replace(/\&feature(.*)/,"").replace(/\&index(.*)/,""); 
      break; 
     case 4: 
     case 5: 
      cleanlink.href = cleanlink.href.replace(/\?(.*)/,""); 

      break; 
     default : 
      cleanlink.href = cleanlink.href.replace(/\&(.*)/,""); 
       } 
    } 
} 

問題是taht這個代碼將只檢查在標準的HTML頁面的YouTube鏈接。添加了AJAX的鏈接（主要在YouTube頻道上）不會被標準化。

即使使用AJAX注入的鏈接，是否有任何方法來運行這個腳本？

Answer 1

沒有一個直接的方式，除非你想運行一個超時你的「正規化」

setInterval(function() { 
    //> code here 
},1000);