1
我有2個表格需要提交我似乎是有限的，因爲它是由mikrotik熱點的2個表格。 在mikrotic路由器的login.html的是多表單提交1提交JavaScript半工作
<html>
<head><title>...</title></head>
<body>
$(if chap-id)
<noscript>
<center><b>JavaScript required. Enable JavaScript to continue.</b></center>
</noscript>
$(endif)
<center>If you are not redirected in a few seconds, click 'continue' below<br>
<form name="redirect" action="http://domain.name/login.php" method="post">
<input type="hidden" name="mac" value="$(mac)">
<input type="hidden" name="ip" value="$(ip)">
<input type="hidden" name="username" value="$(username)">
<input type="hidden" name="link-login" value="$(link-login)">
<input type="hidden" name="link-orig" value="$(link-orig)">
<input type="hidden" name="error" value="$(error)">
<input type="hidden" name="chap-id" value="$(chap-id)">
<input type="hidden" name="chap-challenge" value="$(chap-challenge)">
<input type="hidden" name="link-login-only" value="$(link-login-only)">
<input type="hidden" name="link-orig-esc" value="$(link-orig-esc)">
<input type="hidden" name="mac-esc" value="$(mac-esc)">
<input type="submit" value="continue">
</form>
<script language="JavaScript">
<!--
document.redirect.submit();
//-->
</script></center>
</body>
</html>
所以當時我的login.php是這個
<?php
$mac=$_POST['mac'];
$ip=$_POST['ip'];
$username=$_POST['username'];
$linklogin=$_POST['link-login'];
$linkorig=$_POST['link-orig'];
$error=$_POST['error'];
$chapid=$_POST['chap-id'];
$chapchallenge=$_POST['chap-challenge'];
$linkloginonly=$_POST['link-login-only'];
$linkorigesc=$_POST['link-orig-esc'];
$macesc=$_POST['mac-esc'];
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<head>
<title>mikrotik hotspot > login</title>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<meta http-equiv="pragma" content="no-cache" />
<meta http-equiv="expires" content="-1" />
<style type="text/css">
body {color: #737373; font-size: 10px; font-family: verdana;}
textarea,input,select {
background-color: #FDFBFB;
border: 1px solid #BBBBBB;
padding: 2px;
margin: 1px;
font-size: 14px;
color: #808080;
}
a, a:link, a:visited, a:active { color: #AAAAAA; text-decoration: none; font-size:
10px; }
a:hover { border-bottom: 1px dotted #c1c1c1; color: #AAAAAA; }
img {border: none;}
td { font-size: 14px; color: #7A7A7A; }
</style>
<script language="JavaScript">
function fnSubmit(){
var form1Content = document.getElementById("form1").innerHTML;
var form2Content = document.getElementById("form2").innerHTML;
var form3Content = document.getElementById("form3").innerHTML;
document.getElementById("toSubmit").innerHTML=form1Content+form2Content;
document.forms.toSubmit.submit();
}
</script>
</head>
<body>
<!-- $(if chap-id) -->
<form name="sendin" action="<?php echo $linkloginonly; ?>" method="post" id="form1">
<input type="hidden" name="username" />
<input type="hidden" name="password" />
<input type="hidden" name="dst" value="<?php echo $linkorig; ?>" />
<input type="hidden" name="popup" value="true" />
</form>
<script type="text/javascript" src="./md5.js"></script>
<script type="text/javascript">
<!--
function doLogin() {
<?php if(strlen($chapid) < 1) echo "return true;\n"; ?>
document.sendin.username.value = document.login.username.value;
document.sendin.password.value = hexMD5('<?php echo $chapid; ?>' + document.login.password.value + '<?php echo $chapchallenge; ?>');
document.sendin.submit();
return false;
}
//-->
</script>
<!-- $(endif) -->
<div align="center">
<a href="<?php echo $linkloginonly; ?>?target=lv&dst=<?php echo $linkorigesc; ?>">Hotspot</a>
</div>
<table width="100%" style="margin-top: 10%;">
<tr>
<td align="center" valign="middle">
Please log on to use the mikrotik hotspot service
</div><br />
<table width="240" height="240" style="border: 1px solid #cccccc; padding: 0px;" cellpadding="0" cellspacing="0">
<tr>
<td align="center" valign="bottom" height="175" colspan="2">
<!-- removed $(if chap-id) $(endif) around OnSubmit -->
<form method="POST" action="signin.php" id="form2">
First Name<p><input type="text" name="firstname" size="30"></p>
Surname<p><input type="text" name="lastname" size="30"></p>
Email address <font color="red"> (required)</font><p><input type="text" name="email" size="30"></p>
<input type="submit" value="submit" onclick="javascript:fnSubmit();"/>
</form>
<form name="login" id="form3 action="<?php echo $linkloginonly; ?>" method="post" onSubmit="return doLogin()" >
<input type="hidden" name="dst" value="<?php echo $linkorig; ?>" />
<input type="hidden" name="popup" value="true" />
<table width="100" style="background-color: #ffffff">
<tr><td align="right"></td>
<td><input type="hidden" style="width: 80px" name="username" type="text" value="user2"/></td>
</tr>
<tr><td align="right"></td>
<td><input type="hidden" style="width: 80px" name="password" type="password" value="user2"/></td>
</tr>
<tr><td> </td>
<td><td></td></td></td>
</tr>
</table>
</form>
</td>
</tr>
</table>
<!-- $(if error) -->
<br /><div style="color: #FF8080; font-size: 9px"><?php echo $error; ?></div>
<!-- $(endif) -->
</td>
</tr>
</table>
<script type="text/javascript">
<!--
document.login.username.focus();
//-->
</script>
</body>
</html>
，你可以看到我嘗試自動提交的用戶名和密碼 這樣只有用戶輸入自己的電子郵件地址，要做到這一點，我想一個數據庫 存儲的電子郵件中 與signin.php 這是本
<?php
ini_set('display_errors', 'On');
// Receiving variables
@$pfw_ip= $_SERVER['REMOTE_ADDR'];
@$firstname = addslashes($_POST['firstname']);
@$lastname = addslashes($_POST['lastname']);
@$email = addslashes($_POST['email']);
@$date = addslashes($_POST['date']);
// Validation
if (! ereg('[A-Za-z0-9_-]+\@[A-Za-z0-9_-]+\.[A-Za-z0-9_-]+', $email))
{
die("<p align='center'><font face='Arial' size='3' color='#FF0000'>Please enter a valid email</font></p>");
}
if (strlen($email) == 0)
{
die("<p align='center'><font face='Arial' size='3' color='#FF0000'>Please enter a valid email</font></p>");
}
/* adding user information to the userinfo table */
@$pfw_strQuery = "INSERT INTO userinfo (firstname, lastname, email, creationdate) values ".
"('$firstname', '$lastname', '$email', NOW())";
@$pfw_host = "localhost";
@$pfw_user = "dbusername";
@$pfw_pw = "dbpassword";
@$pfw_db = "database";
$pfw_link = mysql_connect($pfw_host, $pfw_user, $pfw_pw);
if (!$pfw_link) {
die('Could not connect: ' . mysql_error());
}
$pfw_db_selected = mysql_select_db($pfw_db, $pfw_link);
if (!$pfw_db_selected) {
die ('Can not use $pfw_db : ' . mysql_error());
}
//insert new record
$pfw_result = mysql_query($pfw_strQuery);
if (!$pfw_result) {
die('Invalid query: ' . mysql_error());
}
mysql_close($pfw_link);
header('Location: http://www.google.co.uk');
?>
發生的事情是電子郵件地址存儲在MySQL表 但存儲的用戶名和密碼的形式，不通過，我在登錄頁面
我失去了什麼結束了？
感謝所有
哇，這看起來像一個大混亂...你可以嘗試減少你的問題，只有基本部分？ – elclanrs
實際上，我認爲發生的事情是第一個表單被提交將電子郵件插入到數據庫中，但後來我認爲signin.php需要在運行時自動提交第二個表單，那麼它將起作用 – djbridger
任何人都有想法？ – djbridger