如何在Python中顯示數組的百分比

Question

如何打印出數組的百分比？

例如：

如果我有

x = np.array([2,3,1,0,4,3,5,4,3,2,3,4,5,10,15,120,102,10]) 

你如何設置數組的百分比爲零？如果我想保持數組的前10％，並將數組的剩餘90％更改爲零？

預先感謝您？

Answer 1

這會給你90％左右在前面：

x[0:int(len(x)*0.9)] 

，並在後面90％（通過跳過前10％）：

x[int(len(x)*0.1):] 

所以設置最後90 ％至零：

x[int(len(x)*0.1):] = 0 

Answer 2

你可以這樣做：

import numpy as np 

x = np.array([2,3,1,0,4,3,5,4,3,2,3,4,5,10,15,120,102,10]) 

cut_off = int(0.1*len(x)) 

print(len(x), cut_off) 
for idx in range(cut_off,len(x)): 
    x[idx] = 0 

Answer 3

做這個工作嗎？

x = np.array([2,3,1,0,4,3,5,4,3,2,3,4,5,10,15,120,102,10]) 
j=len(x) 
k=(j/100)*10 
for index in range(k,j): 
    x[index]=0 

Answer 4

x = [2,3,1,0,4,3,5,4,3,2,3,4,5,10,15,120,102,10] 
index = 10 * len(x)/100 
x[index:] = [0]*(len(x) - 1 index) 
print x 
>>> x = [2, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] 

Answer 5

這裏是我會做什麼：

x = np.array([2,3,1,0,4,3,5,4,3,2,3,4,5,10,15,120,102,10]) 
change = round(0.9 * len(x)) # changing 90% 
x[-change:] = 0 # change from last value towards beginning of array 
print(x) 

產生它的長度

[2 3 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]