2013-10-03 62 views
0

我試圖SecuSocial模塊添加到我的斯卡拉播放Project.But我得到了一個錯誤如下,值id不是securesocial.core.Identity成員

value id is not a member of securesocial.core.Identity 

In /home/ram/Authentication/app/controllers/Application.scala at line 13. 

Application.scala

package controllers 

import play.api._ 
import play.api.mvc._ 
import securesocial.core.{Identity, Authorization} 

trait Authorization {  
     def isAuthorized(user: Identity): Boolean 
} 

case class WithProvider(provider: String) extends Authorization { 
    def isAuthorized(user: Identity) = { 
     user.id.providerId == provider // ** I got error in this line ** 
    } 
} 



object Application extends Controller with securesocial.core.SecureSocial { 


    def index = SecuredAction { implicit request => 
    Ok(views.html.index(request.user)) 
    } 

    def myAction = SecuredAction(WithProvider("twitter")) { implicit request => 
     // do something here 
     Ok("You can see this because you logged in using Twitter") 
    } 

// // a sample action using the new authorization hook 
// def onlyTwitter = SecuredAction(WithProvider("twitter")) { implicit request => 
// // 
// // Note: If you had a User class and returned an instance of it from UserService, this 
// //   is how you would convert Identity to your own class: 
// // 
// // request.user match { 
// //  case user: User => // do whatever you need with your user class 
// //  case _ => // did not get a User instance, should not happen,log error/thow exception 
// // } 
//  Ok("You can see this because you logged in using Twitter") 
// } 

def page = UserAwareAction { implicit request => 
    val userName = request.user match { 
     case Some(user) => user.fullName 
     case _ => "guest" 
    } 
    Ok("Hello %s".format(userName)) 
    } 

    // you don't want to redirect to the login page for ajax calls so 
    // adding a ajaxCall = true will make SecureSocial return a forbidden error 
    // instead. 
    def ajaxCall = SecuredAction(ajaxCall = true) { implicit request => 
    // return some json 
    } 

} 

build.sbt

name := "Authentication" 

version := "1.0-SNAPSHOT" 

libraryDependencies ++= Seq(
    jdbc, 
    anorm, 
    cache, 
    "com.micronautics" % "securesocial" % "2.2.0" withSources 
) 

resolvers += Resolver.url("sbt-plugin-snapshots", url("http://repo.scala-sbt.org/scalasbt/sbt-plugin-releases/"))(Resolver.ivyStylePatterns)  

play.Project.playScalaSettings 

回答

3

我想你正在使用Secure Social的主快照。這意味着中心回購中的任何更改都將在您構建時下載。

主快照的最新更改如下:Renamed id field in Identity to identityId (breaks backwards compatibility)

所以,你的代碼應該是

case class WithProvider(provider: String) extends Authorization { 
    def isAuthorized(user: Identity) = { 
    user.identityId.providerId == provider 
    } 
} 
+0

我在我的問題補充build.sbt。我的圖書館依賴性是否正確?還是想改變? – Ramprasad

+0

我沒有使用Play 2.2.0,但如果該版本的SecureSocial已發佈,那麼您可以繼續使用它。但我的假設是,我所描述的變化也在2.2.0版本中。所以你必須將'id'改成'identityId'。 – maba

+0

不。不起作用。發生錯誤。 – Ramprasad

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