如何從一個PHP串

Question

除去替代字符我有字符串假設

$str = "abcdefghijklmno"; 

，我想像

$new_str = "acegikmo"; 

字符串我需要使用如果可能的PHP的功能的任何組合的最短方法。

Answer 1

您可以刪除一個字符串的每個第2個字符：

$str = "abcdefghijklmno"; 
$str = preg_replace("/(\w)\w/","$1",$str); 

例子：

abcdefghijklmno will become acegikmo 
1234567890 will become 13579 

Answer 2

嘗試下面的代碼

$string = 'teststring'; //if you want odd places characters then add whitespace at the starting of the string i.e ' teststing' 
$array= str_split($string,1); 
$new_string = ''; 
foreach($array $key=>$data){ 
if($key&1){ 
      $new_string .= $data; 
    } 
} 
echo $new_string; 

Answer 3

用下面的代碼

$string = 'abcdefghijklmno'; 
 
$new_str = ''; 
 
for($i=0;$i<=strlen($string); $i++){ 
 
    if($i%2!=0){ 
 
    $new_str.=$string[$i-1]; 
 
    } 
 
} 
 

 
echo $new_str;

Answer 4

如果你正在運行PHP 5.6您可以使用array_filter：

$string = "abcdefghijklmno"; 

$newstring = join("", 
       array_filter 
       (
        str_split($string), 
        function($k) { 
         return ($k % 2 == 0); 
         }, 
        ARRAY_FILTER_USE_KEY 
       ) 
      ); 
//acegikmo 

http://ideone.com/HC7eL0