4
我遇到了sequelize問題。這裏是我想要做的事:在關係爲空的情況下會出現sequelize
return pointsTransaction.findAndCountAll({
where:{
user_id: userId
},
limit: opts.limit,
offset: opts.offset,
include:[{
model:sequelize.models.pointsPendingtransaction
}]
});
生成的查詢看起來像這樣:
SELECT "pointsTransaction".*,
"pointsPendingtransactions"."transaction_ptr_id" AS "pointsPendingtransactions.transactionPtrId",
"pointsPendingtransactions"."is_active" AS "pointsPendingtransactions.isActive",
"pointsPendingtransactions"."transaction_id" AS "pointsPendingtransactions.transaction_id"
FROM (
SELECT "pointsTransaction"."id",
"pointsTransaction"."date_time" AS "dateTime",
"pointsTransaction"."details",
"pointsTransaction"."points",
"pointsTransaction"."user_id"
FROM "points_transaction" AS "pointsTransaction"
WHERE "pointsTransaction"."user_id" = 10002 LIMIT 1000
) AS "pointsTransaction"
LEFT OUTER JOIN "points_pendingtransaction" AS "pointsPendingtransactions"
ON "pointsTransaction"."id" = "pointsPendingtransactions"."transaction_id"
所以在SQL我只需要添加該行我查詢的結尾,使它的工作:WHERE "pointsPendingtransactions"."transaction_id" IS null
所以我的問題是,我怎麼能做到這一點sequelize?我試過很多不同的方式,但沒有一個工作......
喜歡的東西: 包括:[{ 模型: sequelize.models.pointsPendingtransaction, 其中:{transaction_id:null} }]應該工作儘管我還沒有試過這個m我自己 – Molda
我試了一下,也嘗試了一些基於計數但沒有任何工作。我懷疑由於「findAndCountAll」導致的錯誤 –
當您嘗試Molda的建議時,您會得到什麼錯誤? –