在共享服務器上爲「foreach（）提供的無效參數」

Question

我在這裏使用PHP 5。我有以下代碼：

$data = json_decode($_POST['data']); 
foreach ($data as $obj) { 
...... 

} 

我得到錯誤「的foreach爲無效的論點提供（）」與在foreach功能就行了。這隻發生在我的共享服務器帳戶上。在我的本地網絡服務器上一切正常。 $ _POST ['data']包含有效的JSON字符串。的print_r（$數據）;什麼也沒有顯示......這裏到底怎麼了？

編輯：這真的吹我的腦海裏，但$ _ POST [「數據」]字符串正在使用AJAX發送和我趕上與螢火串並複製到一個JSON測試文件是這樣的：

$data = json_decode('[{"id":3,"name":"John","surname":"Smith","number":6633,"city":"The city","area":"West","street":"West","numar":"15","other":"none"},{"id":3,"name":"John","surname":"Smith","number":6633,"city":"The city","area":"West","street":"West","numar":"15","other":"none"},{"id":3,"name":"John","surname":"Smith","number":6633,"city":"The city","area":"West","street":"West","numar":"15","other":"none"}]'); 
print_r($data); 

它應該是正確的。所以，我會貼得更代碼從功能的煩惱：

function saveData($table) 
{ 
    $data = json_decode($_POST['data']);  

    $db = new MySQL(true); 
    $db->TransactionBegin(); 

    foreach ($data as $obj) { 
    $id = $obj->id; 
    $name = $obj->name; 
} 
} 

檢查了這一點：如果我這樣做：

$data = json_decode('[{"id":3,"name":"John","surname":"Smith","number":6633,"city":"The city","area":"West","street":"West","numar":"15","other":"none"},{"id":3,"name":"John","surname":"Smith","number":6633,"city":"The city","area":"West","street":"West","numar":"15","other":"none"},{"id":3,"name":"John","surname":"Smith","number":6633,"city":"The city","area":"West","street":"West","numar":"15","other":"none"}]'); 
foreach ($data as $obj) { 
...... 

} 

運行完美！因此，似乎有通過電子郵件問題時，我做的事：

$data = json_decode($_POST['data']); 

但$ _ POST [「數據」]輸出一個完美的JSON字符串。這讓我瘋狂。

任何想法？

任何想法？

Answer 1

magic_quotes_gpc的...報價從php.net：

上時，所有的'（單引號），「 （雙引號），\（反斜線）和NULL 字符轉義成一個自動 反斜槓。

事實證明魔術引號共享服務器上啓用了。謝謝你的答案。

Answer 2

json_decode只存在於PHP 5 >= 5.2.0與PECL json >= 1.2.0，所以我的猜測是您的託管使用較低的版本。

Answer 3

$data無效JSON？ （無論是畸形的還是空的）

Answer 4

var_dump($data)將推測顯示$data是null。從the docs：或返回

NULL，如果JSON不能 解碼如果編碼的數據比遞歸限制更深 。

如果您的共享服務器的行爲特殊，或許它的遞歸限制低於本地服務器。