Python文本冒險遊戲不工作

Question

我一直在試圖讓這個Python代碼工作大約一個小時，但我似乎無法修復它。我前幾天進入了Python，所以如果這很容易，那就是原因。

def firstChoice(): 
    time.sleep(2) 
    print('You come across a path, it splits at the end.') 
    time.sleep(1) 
    choice=input('Which path do you take, the left path (1) or the right path (2)? \n') 
    checkChoice() 

def checkChoice(): 
# correct 
    if choice=='1' or choice=='2': 
     correct_choice=randint(1,2) 
     if choice==correct_choice: 
      correct=True 
    if choice!='1' or choice!='2': 
     print('You decide to not take a path, and you die due to random circumstances.') 
     time.sleep(1) 
     print('Take a path next time, or at least take it correctly.') 
     failScreen() 

I've imported everything necessary (time and random)

EDIT: Here's the whole code.

import random 
import time 

choice=0 

def introDisplay(): 
    print('This is the pre-game story.') 
    time.sleep(1) 
    print('It lasts for 5 lines.') 
    time.sleep(1) 
    print('When you can be arsed, fix this.') 
    time.sleep(1) 
    print('Thanks,') 
    time.sleep(1) 
    print('You, from 18/3/17') 
    print() 
    firstChoice() 

def firstChoice(): 
    time.sleep(2) 
    print('You come across a path, it splits at the end.') 
    time.sleep(1) 
    choice=input('Which path do you take, the left path (1) or the right path (2)? \n') 
    checkChoice(choice) 

def checkChoice(choice): 
    correct=False 
    if choice=='1' or choice=='2': 
     correct_choice=random.randint(1,2) 
     if choice==correct_choice: 
      correct=True 
    if choice!='1' and choice!='2': 
     print('You decide to not take a path, and you die due to random circumstances.') 
     time.sleep(1) 
     print('Take a path next time, or at least take it correctly.') 
     failScreen() 




def failScreen(): 
    restart=True 
    print('You have failed.') 
    print('Do you want to retry?') 
    restart1=input('Y or y = Yes. N or n = No. \n') 
    if restart1=='y' or restart1=='Y': 
     restart=True 
    if restart1=='n' or restart1=='N': 
     restart=False 
    if restart1!='n' or restart!='N' or restart!='y' or restart!='Y': 
     failScreen() 
    if restart==True: 
     introDisplay() 
    if restart==False: 
     exit() 

introDisplay() 

Answer 1

首先，如果您正在使用python2.7，則需要知道input（）（如果通過控制檯爲其提供數字），則此功能強制轉換爲int，那麼你需要檢查值一樣，如果choice == 1或者只是改變輸入raw_input()（這是最好的方法），也if choice!='1' and choice!='2':你需要把else:那麼你避免了很多檢查或意外的值。

如果您正在使用的raw_input python3是新的輸入功能，因此，您無需更改

而且，最後，如果你想使用的raw_input（），或者你使用python3您需要更改隨機函數random.choice('1','2')，因爲你是一個比較INT一個海峽，在這裏你有這個代碼爲python2.7變化：

import random 
import time 

choice=0 

def introDisplay(): 
    print('This is the pre-game story.') 
    time.sleep(1) 
    print('It lasts for 5 lines.') 
    time.sleep(1) 
    print('When you can be arsed, fix this.') 
    time.sleep(1) 
    print('Thanks,') 
    time.sleep(1) 
    print('You, from 18/3/17') 
    print() 
    firstChoice() 

def firstChoice(): 
    time.sleep(2) 
    print('You come across a path, it splits at the end.') 
    time.sleep(1) 
    choice=raw_input('Which path do you take, the left path (1) or the right path (2)? \n') 
    checkChoice(choice) 

def checkChoice(choice): 
    correct=False 
    if choice=='1' or choice=='2': 
     correct_choice=random.choice(['1','2']) 
     if choice==correct_choice: 
      correct=True 
      print('You chose the correct path') 
     else: 
      print('You dont chose the correct path') 
    else: 
     print('You decide to not take a path, and you die due to random circumstances.') 
     time.sleep(1) 
     print('Take a path next time, or at least take it correctly.') 
     failScreen() 




def failScreen(): 
    restart=True 
    print('You have failed.') 
    print('Do you want to retry?') 
    restart1=input('Y or y = Yes. N or n = No. \n') 
    if restart1=='y' or restart1=='Y': 
     restart=True 
    if restart1=='n' or restart1=='N': 
     restart=False 
    if restart1!='n' or restart!='N' or restart!='y' or restart!='Y': 
     failScreen() 
    if restart==True: 
     introDisplay() 
    if restart==False: 
     exit() 

introDisplay() 

Answer 2

I guess you are always ending up in the failScreen因爲您的第二個if聲明使用!=1 or !=2，這將導致總是true ...將其更改爲and以查看是否有幫助。

還林不知道如果choice在checkChoice功能可見。在Java中，您需要在函數外部聲明變量