想到我在PHP v5.3.3-1ubuntu9.5 CLI中發現了一個錯誤？

Question

我可能發現了一個錯誤，如果是這樣的話，我該如何報告呢？

這裏是我的本錢：

for ($i = 0; $i <= ($count)-1; ++$i) { 
Lots of code...more then I want to put here 
.... 
..... 
..... 
$mailto = $mailto . $i +1 . ") " . $name . " " . $location . " Type: " . $type . " Status: " . $geostatus . " Difficulty " .$difficulty . "\n" . $region . "\nHidden: " . $hidden . " Last Update: " . $lastupdate . " Last Found: " . $lastfound . "\nDistance: $distance Bearing: $bearing degrees $direction\n\n"; 
} 

echo "$mailto \n"; 

輸出將是這樣的：

4) Morrow Parking - RR Relic LMBT Lat: 39.35455 Lon: -84.133733 Type: Traditional Cache Status: Active Difficulty 3 
City/State: Morrow, OH Warren Co. 
Hidden: Wed June 09 2010 04:00 Last Update: Wed August 03 2011 17:43 Last Found: Wed December 31 1970 19:00 
Distance: 4.31 Bearing: 212 degrees SW 

顯示我只有在列表中的最後一項。 但是，如果我只是稍微改變代碼如下：

for ($i = 0; $i <= ($count)-1; ++$i) { 
Lots of code...more then I want to put here 
.... 
..... 
..... 
$cc = $i +1; 
$mailto = $mailto . $cc . ") " . $name . " " . $location . " Type: " . $type . " Status: " . $geostatus . " Difficulty " .$difficulty . "\n" . $region . "\nHidden: " . $hidden . " Last Update: " . $lastupdate . " Last Found: " . $lastfound . "\nDistance: $distance Bearing: $bearing degrees $direction\n\n"; 
} 

echo "$mailto \n"; 

我得到充分的輸出，因爲我希望看到：

1) Uranus - The Solar System - Lil Miami Bike Trail Lat: 39.415517 Lon: -84.103383 Type: Traditional Cache Status: Active Difficulty 1.5 
City/State: , OH Warren Co. 
Hidden: Sun October 17 2010 04:00 Last Update: Fri August 05 2011 18:25 Last Found: Wed December 31 1970 19:00 
Distance: 0.92 Bearing: 309 degrees NW 

2) 79 Lat: 39.394517 Lon: -84.096533 Type: Traditional Cache Status: Active Difficulty 2 
City/State: , OH Warren Co. 
Hidden: Sun May 30 2010 04:00 Last Update: Wed August 03 2011 17:42 Last Found: Wed December 31 1970 19:00 
Distance: 0.93 Bearing: 201 degrees S 

3) RR Relic - Oregonia Lat: 39.462583 Lon: -84.100383 Type: Traditional Cache Status: Active Difficulty 1.5 
City/State: Oregonia, OH Warren Co. 
Hidden: Sun May 02 2010 04:00 Last Update: Wed August 03 2011 17:41 Last Found: Wed December 31 1970 19:00 
Distance: 3.88 Bearing: 351 degrees N 

4) Morrow Parking - RR Relic LMBT Lat: 39.35455 Lon: -84.133733 Type: Traditional Cache Status: Active Difficulty 3 
City/State: Morrow, OH Warren Co. 
Hidden: Wed June 09 2010 04:00 Last Update: Wed August 03 2011 17:43 Last Found: Wed December 31 1970 19:00 
Distance: 4.31 Bearing: 212 degrees SW 

我有沒有發現一個bug，還是我做錯事的第一種方式，並在第二種方式更正？

如果我確實發現了一個錯誤，我該如何報告。

PHP v5.3.3在Ubuntu 10.10上運行CLI版本謝謝。

Answer 1

在代碼的第一位，更改：

$mailto = $mailto . $i +1 . ") " . $name . " " . $location . " Type: " . $type . " Status: " . $geostatus . " Difficulty " .$difficulty . "\n" . $region . "\nHidden: " . $hidden . " Last Update: " . $lastupdate . " Last Found: " . $lastfound . "\nDistance: $distance Bearing: $bearing degrees $direction\n\n"; 

到

$mailto = $mailto . ($i +1) . ") " . $name . " " . $location . " Type: " . $type . " Status: " . $geostatus . " Difficulty " .$difficulty . "\n" . $region . "\nHidden: " . $hidden . " Last Update: " . $lastupdate . " Last Found: " . $lastfound . "\nDistance: $distance Bearing: $bearing degrees $direction\n\n"; 

我懷疑你剛剛的操作錯誤的順序。

Answer 2

它與運算符優先級有關。這裏有一個簡單的例子：

$i=1;// doesn't matter what this value is 
$s = " alpha " . $i+1 . " beta " . " gamma<br>\n"; 
echo $s; // 1 beta gamma 

$s = " alpha " . ($i+1) . " beta " . " gamma<br>\n"; 
echo $s; // alpha 2 beta gamma 

在第一種情況下的異常行爲，甚至發生，如果你的貓加入到（INT）。

$s = " alpha " . (int)$i+1 . " beta " . " gamma<br>\n";