Xcode iOS：將int轉換爲NSString

Question

我試圖從UIPicker中獲取avalue，該值填充了整數，整數從NSMutableArray中拉出。我試圖將拉的值轉換爲實際的整數。

我在.M嘗試這樣做：

int pickednumber; 


...... 

-(void) pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component{ 


NSString *numbers = [arrayNumbers objectAtIndex:[pickerView selectedRowInComponent:0]]; 

pickednumber = [NSString stringWithFormat:@"%d", numbers]; 

NSLog(@"Picked number %@ ", numbers); 

} 

我得到的錯誤在pickednumber =行：不相容指針到整數轉換分配給從「ID」「INT」。 我在做什麼錯？

消息在3:05 PM

Answer 1

NSString *intString = [NSString stringWithFormat:@"%d", myInt]; 

http://forums.macrumors.com/showthread.php?t=448594

Answer 2

NSString編輯者Sounddesigner上12年3月8日具有舒適方法獲取文本的整數值

做到這一點

pickednumber = [numbers intValue]; 

NSLog(@"Picked number %d ", numbers); // not %@ ..%@ is for objects .. not int 

Answer 3

爲整數轉換成的NSString：

NSString *string = [NSString stringWithFormat:@"%i",integerNumber]; 

要轉換的NSString INT：

int number = [string integerValue];