如何方便獲取到今天，昨天一天前兩日的前數據？

Question

$active_count1_end=date('Y-m-d'); 
$active_count1_end.=" 23:59:59"; 
$active_count1_start=date('Y-m-d'); 
$active_count1_start.=" 00:00:00"; 
$count10=$today->query("select count(*) as count1 from talk where time1 between '". $active_count1_start."' and '".$active_count1_end."'"); 
$count11=$today->query("select count(*) as count2 from reply where time2 between '". $active_count1_start."' and '".$active_count1_end."'"); 
$count1=$count10[0][count1]+$count11[0][count2]; 

$active_count2_end=strtotime($active_count1_end)-24*3600; 
$active_count2_end=date('Y-m-d',$active_count2_end); 
$active_count2_end.=" 23:59:59"; 
$active_count2_start=strtotime($active_count1_end)-24*3600; 
$active_count2_start=date('Y-m-d',$active_count2_start); 
$active_count2_start.=" 00:00:00"; 
$count20=$today->query("select count(*) as count1 from talk where time1 between '". $active_count2_start."' and '".$active_count2_end."'"); 
$count21=$today->query("select count(*) as count2 from reply where time2 between '". $active_count2_start."' and '".$active_count2_end."'"); 
$count2=$count20[0][count1]+$count21[0][count2]; 

$active_count3_end=strtotime($active_count2_end)-24*3600; 
$active_count3_end=date('Y-m-d',$active_count3_end); 
$active_count3_end.=" 23:59:59"; 
$active_count3_start=strtotime($active_count2_end)-24*3600; 
$active_count3_start=date('Y-m-d',$active_count3_start); 
$active_count3_start.=" 00:00:00"; 
$count30=$today->query("select count(*) as count1 from talk where time1 between '". $active_count3_start."' and '".$active_count3_end."'"); 
$count31=$today->query("select count(*) as count2 from reply where time2 between '". $active_count3_start."' and '".$active_count3_end."'"); 
$count3=$count30[0][count1]+$count31[0][count2]; 

$active_count4_end=strtotime($active_count3_end)-24*3600; 
$active_count4_end=date('Y-m-d',$active_count4_end); 
$active_count4_end.=" 23:59:59"; 
$active_count4_start=strtotime($active_count3_end)-24*3600; 
$active_count4_start=date('Y-m-d',$active_count4_start); 
$active_count4_start.=" 00:00:00"; 
$count40=$today->query("select count(*) as count1 from talk where time1 between '". $active_count4_start."' and '".$active_count4_end."'"); 
$count41=$today->query("select count(*) as count2 from reply where time2 between '". $active_count4_start."' and '".$active_count4_end."'"); 
$count4=$count40[0][count1]+$count41[0][count2]; 

的代碼是用使一個論壇， $count1就是今天的數據， $count2是昨天的數據， $count3。 ..， $count4 ... 當然，代碼沒有錯誤，但它看起來不太好。 你有代碼的一些優化方法嗎？

Answer 1

您最好閱讀本文。

http://www.php.net/manual/en/datetime.formats.relative.php