2012-08-15 231 views

回答

3

使用傳遞給你的doPost方法在servlet

public class ExampServlet extends HttpServlet { 
    public void doPost(HttpServletRequest request,HttpServletResponse response)throws ServletException, IOException 
    { 
    // to accept the json data 

    String jsonData = request.getParameter("json"); 

    // to send out the json data 

    response.setContentType("application/json"); 
    PrintWriter out = response.getWriter(); 
    out.println(jsonData) ; 
    out.close()/
    } 
+0

HttpServletRequest的和HttpServletResponse參數你能分享一個例子嗎? – Alok 2012-08-15 10:40:35