搜索我在我的數據庫3個表,Yii的CGridView排序,並與關係表
圖片低於,我按照http://www.yiiframework.com/wiki/281/searching-and-sorting-by-related-model-in-cgridview/
拿到最後一格與搜索和排序的目的。所以我必須連接2個表中search()
功能像
public function search() { // Warning: Please modify the following code to remove attributes that // should not be searched. $criteria=new CDbCriteria; $criteria->with = array('bposite'); $criteria->together = false; $criteria->with = array('client'); $criteria->compare('id',$this->id); // $criteria->compare('client_id',$this->client_id); // $criteria->compare('bposite_id',$this->bposite_id); $criteria->compare('userid',$this->userid,true); $criteria->compare('password',$this->password,true); $criteria->compare('bposite.name', $this->bposite_search, true); $criteria->compare('client.name', $this->client_search, true); return new CActiveDataProvider($this, array( 'criteria'=>$criteria, 'sort'=>array( 'attributes'=>array( 'client_search'=>array( 'asc'=>'client.name', 'desc'=>'client.name DESC', ), 'bposite_search'=>array( 'asc'=>'bposite.name', 'desc'=>'bposite.name DESC', ), '*', ), ), )); } }
但我得到的結果對於客戶,bposite SEACH和排序是顯示像
> Error 500: <h1>CDbException</h1>
> <p>CDbCommand failed to execute the SQL statement: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'bposite.name'
> in 'where clause'. The SQL statement executed was: SELECT
> COUNT(DISTINCT `t`.`id`) FROM `clientbposites` `t` LEFT OUTER JOIN
> `client` `client` ON (`t`.`client_id`=`client`.`id`) WHERE
> (bposite.name LIKE :ycp0)
> (D:\wamp\www\yi\framework\db\CDbCommand.php:516)</p><pre>#0
> D:\wamp\www\yi\framework\db\CDbCommand.php(411):
> CDbCommand->queryInternal('fetchColumn', 0, Array)
how can implement non-related table with cgridview search and sort options.
當你將'$ criteria-> together'改爲'true'時出錯嗎? – dInGd0nG
沒有錯誤,只是嘗試。我從下面得到了答案.. – bala