如何在iphone中創建聯繫人二維碼

Question

我正在爲Qr生成器應用程序工作，爲此我有很好的kyupay庫。

在該庫中，我需要傳遞字符串值並返回QR圖像。

它的工作文本，電子郵件和等好...

，但現在我想創建QR圖片的聯繫和活動，我不知道如何做到這一點。

所以我的問題是應該是什麼邏輯？

請給我建議，或者如果你有代碼，那麼請分享它。

Answer 1

感謝您回覆我的問題。

我終於創建了一個返回聯繫人Qr碼字符串的函數。

這很容易但太長。

我們必須檢查來自用戶的數據輸入並按照數據添加sting並創建字符串。

我發佈我的代碼，以便它可以幫助他人並節省他們的時間。

-(NSString *)GenerateStringForContact{ 

    NSString *str = @""; 
    NSMutableArray *arr1 =[[NSMutableArray alloc] init]; 

    for (int i=0 ; i<[arrayAttributeName count]; i++) { 

     if ([[arrayAttributeName objectAtIndex:i] isEqualToString:@"First Name"]) { 
      if ([strContactType isEqualToString:@"ContactMecard"]) { 
      [arr1 addObject:@"N:"]; 
      }else{ 
      [arr1 addObject:@"FN:"]; 
      } 
     }else if ([[arrayAttributeName objectAtIndex:i] isEqualToString:@"Last Name"]) { 
//   [arr1 addObject:@"N:"]; 
     }else if ([[arrayAttributeName objectAtIndex:i] isEqualToString:@"Phone"]) { 
      [arr1 addObject:@"TEL:"]; 
     }else if ([[arrayAttributeName objectAtIndex:i] isEqualToString:@"Email"]) { 
      [arr1 addObject:@"EMAIL:"]; 
     }else if ([[arrayAttributeName objectAtIndex:i] isEqualToString:@"URL"]) { 
      [arr1 addObject:@"URL:"]; 
     }else if ([[arrayAttributeName objectAtIndex:i] isEqualToString:@"Nickname"]) { 
      [arr1 addObject:@"NICKNAME:"]; 
     }else if ([[arrayAttributeName objectAtIndex:i] isEqualToString:@"Title"]) { 
      [arr1 addObject:@"TITLE:"]; 
     }else if ([[arrayAttributeName objectAtIndex:i] isEqualToString:@"Organization"]) { 
      [arr1 addObject:@"ORG:"]; 
     }else if ([[arrayAttributeName objectAtIndex:i] isEqualToString:@"Birthday"]) { 
      [arr1 addObject:@"BDAY:"]; 
     }else if ([[arrayAttributeName objectAtIndex:i] isEqualToString:@"Note"]) { 
      [arr1 addObject:@"NOTE:"]; 
     } 

    } 

    NSMutableArray *contDetail = arrayAttributeValue; 

    if ([strContactType isEqualToString:@"ContactMecard"]) { 
     str = @"MECARD:"; 
//   arr1 = [[NSArray alloc] initWithObjects:@"N:",@"TEL:",@"EMAIL:",@"URL:",@"NOTE:",@"NICKNAME:",@"BDAY:",@"ADR:",nil]; 

    }else{ 

     str = @"BEGIN:VCARD"; 
//  arr1 = [[NSArray alloc] initWithObjects:@"N:",@"TEL:",@"EMAIL:",@"URL:",@"NOTE:",@"NICKNAME:",@"BDAY:",@"ADR:",@"TITLE:",@"ORG:",nil]; 
    } 

    BOOL count = TRUE; 
    for (int i =0; i <[contDetail count]; i++) { 

     if (![[contDetail objectAtIndex:i] isEqualToString:@""]) { 

      NSString *tmp2 =@""; 

      if (i == 0 || i == 1) { 
       if (count) { 


        if ([strContactType isEqualToString:@"ContactMecard"]) { 

         tmp2 = [NSString stringWithFormat:@"%@,%@",[contDetail objectAtIndex:0],[contDetail objectAtIndex:1]]; 

         NSString *tmp = [NSString stringWithFormat:@"%@%@",[arr1 objectAtIndex:i],tmp2]; 

        str = [NSString stringWithFormat:@"%@;%@",str,tmp]; 

        }else{ 
         tmp2 = [NSString stringWithFormat:@"%@ %@",[contDetail objectAtIndex:0],[contDetail objectAtIndex:1]]; 

         NSString *tmp = [NSString stringWithFormat:@"%@%@",[arr1 objectAtIndex:i],tmp2]; 

         str = [NSString stringWithFormat:@"%@\n%@",str,tmp]; 
        } 

        count = FALSE; 
       } 

      }else{ 

       tmp2 = [contDetail objectAtIndex:i]; 
       NSString *tmp = [NSString stringWithFormat:@"%@%@",[arr1 objectAtIndex:i-1],tmp2]; 

       if ([strContactType isEqualToString:@"ContactMecard"]) { 

        str = [NSString stringWithFormat:@"%@;%@",str,tmp]; 

       }else{ 
        str = [NSString stringWithFormat:@"%@\n%@",str,tmp]; 
       } 


      } 

     } 
    } 

    if (![strContactType isEqualToString:@"ContactMecard"]) { 
     str = [NSString stringWithFormat:@"%@\nEND:VCARD",str]; 


    } 
    NSLog(@"here string for generate code %@",str);  

    return str; 
} 

由於....

Answer 2

如果您在此網站創建聯繫人QR代碼：http://zxing.appspot.com/generator/它爲您提供了它用來創建QR碼的字符串。也許你可以用它作爲靈感？