解析錯誤：語法錯誤，意外的'。'在PHP中？

Question

我得到解析錯誤：語法錯誤，意外的'。'在C：\ xampp \ htdocs \ PHPExercise \ go4shop \ header.php中爲

php require("bar.php"); 
echo "<hr />"; 
if (isset($_SESSION['SESS_LOGGEDIN']) == T RUE) { 
    echo "Logged in as <strong>".$_SESSION['SESS_USERNAME']."</strong>[<a href=" & quot;.$config_basedir. & quot; 
    logout.php ">logout</a>]"; 
} else { 
    echo "<a href=" & quot;.$config_basedir. & quot; 
    login.php ">Login</a>"; 
} 

Answer 1

重寫您的代碼。使用以下代碼：

php require("bar.php"); 
echo "<hr/>"; 
if (isset($_SESSION['SESS_LOGGEDIN'])) { 
    echo "Logged in as <strong>".$_SESSION['SESS_USERNAME']."</strong>[<a href='".$config_basedir."logout.php'>logout</a>]"; 
} else { 
    echo "<a href='".$config_basedir."login.php'>Login</a>"; 
} 

從代碼中刪除"。並使代碼可行。