與mysqli的當前工作代碼如下。我想將其轉換爲預先準備的語句。基本上有三個sql查詢需要轉換爲準備好的語句。第一部分對我來說是最困難的部分,我想出了計算價值的準備方法,而我最終還是設法弄清楚了。將mysqli分頁轉換爲預處理語句分頁
<?php
// Script and tutorial written by Adam Khoury @ developphp.com
// Line by line explanation : youtube.com/watch?v=T2QFNu_mivw
include_once("storescripts/connect_to_mysqli.php");
// This first query is just to get the total count of rows
$sql2 = "SELECT COUNT(id) FROM products ";
$query2 = mysqli_query($myConnection, $sql2);
$row = mysqli_fetch_row($query2);
// Here we have the total row count
$rows = $row[0];
// This is the number of results we want displayed per page
$page_rows = 10;
// This tells us the page number of our last page
$last = ceil($rows/$page_rows);
// This makes sure $last cannot be less than 1
if($last < 1){
$last = 1;
}
// Establish the $pagenum variable
$pagenum = 1;
// Get pagenum from URL vars if it is present, else it is = 1
if(isset($_GET['pn'])){
$pagenum = preg_replace('#[^0-9]#', '', $_GET['pn']);
}
// This makes sure the page number isn't below 1, or more than our $last page
if ($pagenum < 1) {
$pagenum = 1;
} else if ($pagenum > $last) {
$pagenum = $last;
}
// This sets the range of rows to query for the chosen $pagenum
$limit = 'LIMIT ' .($pagenum - 1) * $page_rows .',' .$page_rows;
// This is your query again, it is for grabbing just one page worth of rows by applying $limit
$sql = "SELECT id,product_name, price FROM products ORDER BY product_name DESC $limit";
$query = mysqli_query($myConnection, $sql);
// This shows the user what page they are on, and the total number of pages
$textline1 = "Products (<b>$rows</b>)";
$textline2 = "Page <b>$pagenum</b> of <b>$last</b>";
// Establish the $paginationCtrls variable
$paginationCtrls = '';
// If there is more than 1 page worth of results
if($last != 1){
/* First we check if we are on page one. If we are then we don't need a link to
the previous page or the first page so we do nothing. If we aren't then we
generate links to the first page, and to the previous page. */
if ($pagenum > 1) {
$previous = $pagenum - 1;
$paginationCtrls .= '<a href="'.$_SERVER['PHP_SELF'].'?pn='.$previous.'">Previous</a> ';
// Render clickable number links that should appear on the left of the target page number
for($i = $pagenum-4; $i < $pagenum; $i++){
if($i > 0){
$paginationCtrls .= '<a href="'.$_SERVER['PHP_SELF'].'?pn='.$i.'">'.$i.'</a> ';
}
}
}
// Render the target page number, but without it being a link
$paginationCtrls .= ''.$pagenum.' ';
// Render clickable number links that should appear on the right of the target page number
for($i = $pagenum+1; $i <= $last; $i++){
$paginationCtrls .= '<a href="'.$_SERVER['PHP_SELF'].'?pn='.$i.'">'.$i.'</a> ';
if($i >= $pagenum+4){
break;
}
}
// This does the same as above, only checking if we are on the last page, and then generating the "Next"
if ($pagenum != $last) {
$next = $pagenum + 1;
$paginationCtrls .= ' <a href="'.$_SERVER['PHP_SELF'].'?pn='.$next.'">Next</a> ';
}
}
$dynamicList = '';
while($row = mysqli_fetch_array($query, MYSQLI_ASSOC)){
$id = $row["id"];
$product_name = $row["product_name"];
$price = $row["price"];
$dynamicList .= "
<li><div class='product'>
<a href='product.php?id=$id' class='info'>
<span class='holder'>
<img src='inventory_images/$id.jpg' alt='$product_name' />
<span class='book-name'>$product_name</span>
</a>
<a href='product.php?id=$id' class='buy-btn'>RM<span class='price'>$price</span></a>
</div>
</li>
";
}
// Close your database connection
mysqli_close($myConnection);
?>
<!DOCTYPE html>
<html>
<head>
<style type="text/css">
body{ font-family:"Trebuchet MS", Arial, Helvetica, sans-serif;}
div#pagination_controls{font-size:21px;}
div#pagination_controls > a{ color:#06F; }
div#pagination_controls > a:visited{ color:#06F; }
</style>
</head>
<body>
<div>
<h2><?php echo $textline1; ?> Paged</h2>
<p><?php echo $textline2; ?></p>
<p><?php echo $dynamicList; ?></p>
<div id="pagination_controls"><?php echo $paginationCtrls; ?></div>
</div>
</body>
</html>
由於事先的任何援助
爲什麼while和array在這裏? –
我其實只是試圖檢索計數number..any更好的方式來獲得這個值? –