如何使用數據庫中的數據創建JavaScript對象？

Question

我想創建一個JavaScript對象，如下所示。

var codropsEvents = { 
    '02-02-2017' : '<span>Some txt from database</span><span>Some txt from database</span>', 
    '02-05-2017' : '<span>Some txt from database</span><span>Some txt from database</span>' 
}; 

爲此，我開發的js函數如下。

function setEventsCalendar() { 
    var codropsEvents 
    try { 
     $.ajax({ 
      type: "POST", 
      url: "calendarData.php", 
      dataType: "text", 
      async: false, 
      success: function(msg) { 
       codropsEvents = "{" + msg + "}"; 
       codropsEvents = JSON.parse(codropsEvents); 
      } 
     }); 

     return codropsEvents; 
    } catch(ex) { 
     alert(ex); 
    } 
} 

var codropsEvents = setEventsCalendar(); 

calendarData.php文件生成以下爲字符串（包括所有的冒號，逗號，標籤等）

'02-02-2017' : '<span>Some txt from database</span><span>Some txt from database</span>', '02-08-2017' : '<span>Some txt from database</span><span>Some txt from database</span>' 

如何創建使用字符串的JS對象？或者其他任何適當的方式來獲得預期的結果。

謝謝！

Answer 1

你可以讓一個數組像PHP的

$dataArray = ['02-02-2017' => '<span>Some txt from database</span><span>Some txt from database</span>', 
       '02-05-2017' => '<span>Some txt from database</span><span>Some txt from database</span>']; 
// and this array to json string and print it, 
echo json_encode($dataArray,JSON_FORCE_OBJECT); 

現在阿賈克斯的一部分，你可以簡單地通過改變數據類型爲json得到JSON格式的數據;成功函數的msg參數是javascript對象或者成功函數裏面有codropsEvents = JSON.parse(msg);這樣的代碼。