傳遞參數Telerik的報告

Question

我有一個Telerik的報表項目添加到我的網站，我想傳遞參數給它，但我收到以下錯誤

Error:

Object reference not set to an instance of an object.

Asp.net代碼

protected void Page_Load(object sender, EventArgs e) 
{ 
    if (!Page.IsPostBack) 
    { 
     MembershipCard rpt = new MembershipCard(); 
     // Error occuring here 
     rpt.ReportParameters["@MemberID"].Value = "5"; // Request["MemberID"]; 
     ReportViewer1.Report = rpt; 
    }   
} 

Telerik的報告類

public MembershipCard() 
    { 
     /// <summary> 
     /// Required for telerik Reporting designer support 
     /// </summary> 
     InitializeComponent(); 
     this.DataSource = null; 
    } 

    private void MembershipCard_NeedDataSource(object sender, EventArgs e) 
    { 
     string proc = "rpt_MembershipCard" + this.ReportParameters["@MemberID"].Value.ToString(); 
     SqlDataAdapter adapter = new SqlDataAdapter(proc, "Data Source=(local); Initial Catalog= northwind; intergrated security = True"); 
     DataSet dataSet = new DataSet(); 
     adapter.Fill(dataSet); 
     (sender as Telerik.Reporting.Processing.Report).DataSource = dataSet; 
    } 

可有人請點我在正確的方向我一直沒能找到任何與互聯網相關的東西。

Answer 1

問題是你沒有提供參數。嘗試改變：

rpt.ReportParameters.Add("MemberID", "5"); 

和：

string proc = this.ReportParameters["MemberID"].Value.ToString(); 

另外，如果你在溶液DataSet.xsd文件，利用其產生的TableAdapter。

實例存儲過程：

using System.Data; 
using YourNamespace.StoredProcedureNameTableAdapter; 

//Keep in mind StoredProcedureName is taken from SP name in your database 
//when you add DataSet.xsd to your solution by default if you don't change anything 

private void ClassName_NeedDataSource(object sender, EventArgs e) 
{ 
    int someID = int.Parse(this.ReportParameters["ParameterID"].Value.ToString()); 
    StoredProcedureNameTableAdapter adapter = new StoredProcedureNameTableAdapter(); 
    DataSetFile.StoredProcedureNameDataTable data = adapter.GetData(someID); //DataSetFile is DataSetFile.xsd and GetData is method name you defined on DataSetFile.xsd creation 
    ((Telerik.Reporting.Processing.Report)sender).DataSource = data.AsDataView(); 
}