所以這裏是代碼。這是一個日曆程序的框架,查找一個月和一年。我不確定爲什麼我們的老師想要命令行參數,所以現在忽略它,除非它影響我的代碼。在頁面底部,我將顯示輸出。當我收到一個輸出時,儘管在該方法中調用了用戶輸入,但第二種方法(即處理幾個月)的任何內容都不會顯示。我希望我的程序能夠首先詢問用戶想要查看的年份,然後查看該月份。我確定我犯了一些明顯的錯誤,但是有人能指出我的方向嗎?Java:我的語句int他主要的方法是打印,但沒有在我的其他方法
package calendardisplay;
/**
*
* @author TheDancingPope
*/
import java.util.Scanner;
public class CalendarDisplay
{
static Scanner scan = new Scanner(System.in);
public static final String MONTH_NAME[] = {"","Jan","Feb","Mar",
"Apr", "May","June",
"Jul", "Aug", "Sep",
"Oct", "Nov", "Dec"};
public static void outputMonthName(int month)
{
System.out.println(MONTH_NAME[month]);
}
public static void main(String[] args)
{
for (int i = 1; i < MONTH_NAME.length; i++)
{
System.out.println("Month number:" + i +
"\nis Month Name:\n" + MONTH_NAME[i]);
}
//Processes command line argument
System.out.println("Number of command line arguments: " + args.length);
for(int i = 0; i < args.length; i++)
{
System.out.println("Argument " + i + ": " + args[i]);
}
//This next section handles the leap year scanner. Based on the
//calculation below, paired with the user input, I will be able to tell
//whether or not they picked a leap year.
System.out.println("Please choose a year");
int yearChosen = scan.nextInt();
boolean isLeapYear = ((yearChosen % 4 == 0) && (yearChosen % 100 !=0)
|| (yearChosen % 400 == 0));
System.out.println("You chose\n" + yearChosen);
if (isLeapYear)
{
System.out.println (yearChosen + "\n is a leap year.");
} else
System.out.println(yearChosen + "\n is not a leap year.");
}
//This is where the months are processed. In here, I will sort through
//the months chosen via the user, and based on their month, I will bring up
//a formatted calendar for that month, with the correct amount of days in it.
public static int monthTime()
{
System.out.println("Please chose a month:\n");
int monthChosen = scan.nextInt();
String monthString;
switch (monthChosen)
{
case 1: monthString = "January";
break;
case 2: monthString = "February";
break;
case 3: monthString = "March";
break;
case 4: monthString = "April";
break;
case 5: monthString = "May";
break;
case 6: monthString = "June";
break;
case 7: monthString = "July";
break;
case 8: monthString = "August";
break;
case 9: monthString = "September";
break;
case 10: monthString = "October";
break;
case 11: monthString = "November";
break;
case 12: monthString = "December";
break;
default: monthString = "Invalid month";
break;
}
System.out.println("You chose:\n" + monthString);
return monthChosen;
}
}
當我運行它,我得到了我的小NetBeans的盒子下面的輸出下面我的代碼:
run:
Month number:1
is Month Name:
Jan
Month number:2
is Month Name:
Feb
Month number:3
is Month Name:
Mar
Month number:4
is Month Name:
Apr
Month number:5
is Month Name:
May
Month number:6
is Month Name:
June
Month number:7
is Month Name:
Jul
Month number:8
is Month Name:
Aug
Month number:9
is Month Name:
Sep
Month number:10
is Month Name:
Oct
Month number:11
is Month Name:
Nov
Month number:12
is Month Name:
Dec
Number of command line arguments: 0
Please choose a year
2015
You chose
2015
2015
is not a leap year.
BUILD SUCCESSFUL (total time: 5 seconds)
它給了我一個提示,當用戶在一年內進入,而不是月。我已經提示程序在該方法中初始化一個int掃描器,但是我什麼也沒得到。我在做什麼錯?
感謝您接受我的回答:D –