Android Webview - 如何在默認瀏覽器中打開外部鏈接？

我想做一個webview應用程序，但我不擅長它。Android Webview - 如何在默認瀏覽器中打開外部鏈接？

只是我想這樣做：我有一個網站，我想在默認瀏覽器中打開外部鏈接，如目標_blank。

我的活動：

public class MainActivity extends AppCompatActivity { 

DrawerLayout drawerLayout; 
ActionBarDrawerToggle drawerToggle; 
NavigationView navigation; 

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_main); 
    OneSignal.startInit(this).init(); 
    initInstances(); 
    WebView myWebView = (WebView) findViewById(R.id.webView1); 
    myWebView.loadUrl("http://mywebsite.domain.com/myprofile/"); 
    myWebView.setWebViewClient(new WebViewClient()); 
} 

private void initInstances() { 
    getSupportActionBar().setHomeButtonEnabled(true); 
    getSupportActionBar().setDisplayHomeAsUpEnabled(true); 

    drawerLayout = (DrawerLayout) findViewById(R.id.drawerLayout); 
    drawerToggle = new ActionBarDrawerToggle(MainActivity.this, drawerLayout, R.string.hello_world, R.string.hello_world); 
    drawerLayout.setDrawerListener(drawerToggle); 

    navigation = (NavigationView) findViewById(R.id.navigation_view); 
    navigation.setNavigationItemSelectedListener(new NavigationView.OnNavigationItemSelectedListener() { 

    String menu1 = "https://mywebsite.domain.com/myprofile/"; 
    String menu2 = "https://mywebsite.domain.com/exit"; 
    String menu3 = "https://mywebsite.domain.com/discover/"; 
    String menu4 = "https://mywebsite.domain.com/settings/"; 
    String menu5 = "https://mywebsite.domain.com/language"; 
    String menu6 = "https://mywebsite.domain.com/vipmembership"; 

     @Override 
     public boolean onNavigationItemSelected(MenuItem menuItem) { 
      int id = menuItem.getItemId(); 
      WebView myWebView = (WebView) findViewById(R.id.webView1); 
      myWebView.setWebViewClient(new WebViewClient()); 
      switch (id) { 
       case R.id.navigation_item_1: 
        myWebView.loadUrl(this.menu1); 
        break; 
       case R.id.navigation_item_2: 
        myWebView.loadUrl(this.menu2); 
        break; 
       case R.id.navigation_item_3: 
        myWebView.loadUrl(this.menu3); 
        break; 
       case R.id.navigation_item_4: 
        myWebView.loadUrl(this.menu4); 
        break; 
       case R.id.navigation_item_5: 
        myWebView.loadUrl(this.menu5); 
        break; 
       case R.id.navigation_item_6: 
        myWebView.loadUrl(this.menu6); 
        break; 
      } 
      return false; 
     } 
    }); 


} 

@Override 
public void onPostCreate(Bundle savedInstanceState) { 
    super.onPostCreate(savedInstanceState); 
    drawerToggle.syncState(); 
} 

@Override 
public void onConfigurationChanged(Configuration newConfig) { 
    super.onConfigurationChanged(newConfig); 
    drawerToggle.onConfigurationChanged(newConfig); 
} 

@Override 
public boolean onCreateOptionsMenu(Menu menu) { 
    // Inflate the menu; this adds items to the action bar if it is present. 
    getMenuInflater().inflate(R.menu.menu_main, menu); 
    return true; 
} 

@Override 
public boolean onOptionsItemSelected(MenuItem item) { 
    if (drawerToggle.onOptionsItemSelected(item)) 
     return true; 

    // Handle action bar item clicks here. The action bar will 
    // automatically handle clicks on the Home/Up button, so long 
    // as you specify a parent activity in AndroidManifest.xml. 
    int id = item.getItemId(); 

    //noinspection SimplifiableIfStatement 
    if (id == R.id.action_settings) { 
     return true; 
    } 

    return super.onOptionsItemSelected(item); 
}}

我累了這麼多的代碼它，但它沒有工作。非常感謝。

來源

2017-02-07 Onur YIlmaz

你有沒有試過這個http://stackoverflow.com/questions/17994750/open-external-links-in-the-browser-with-android-webview – Maximosaic

我厭倦了這一點，但不起作用。 –

你得的Intent發送到默認的Web瀏覽器，以打開瀏覽器的鏈接，所以也許是這樣的：以這種方式

創建擴展WebViewClient一類：

private class MyCustomWebViewClient extends WebViewClient { 

    @Override 
    public boolean shouldOverrideUrlLoading(WebView view, String url) { 
     if(url.contains("https://mywebsite.domain.com")) { 
      Intent i = new Intent(Intent.ACTION_VIEW, Uri.parse(url)); 
      startActivity(i); 
     } else { 
      view.loadUrl(url); 
     } 
     return true; 
    } 
}

在你MainActivity，在onCreate方法，設置MyCustomWebViewClient 調用使用loadURL方法之前，像這樣：

public class MainActivity extends AppCompatActivity { 

    DrawerLayout drawerLayout; 
    ActionBarDrawerToggle drawerToggle; 
    NavigationView navigation; 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 
     OneSignal.startInit(this).init(); 
     initInstances(); 
     WebView myWebView = (WebView) findViewById(R.id.webView1); 
     myWebView.setWebViewClient(new MyCustomWebViewClient()); 
     myWebView.loadUrl("http://mywebsite.domain.com/myprofile/"); 
    } 

    // the rest of your code

來源

2017-02-07 22:17:48

我會試試這個。謝謝。 –

不客氣。不要忘了接受最好的答案，請 –

當我修改你的代碼時，非常感謝！ :) –

Android Webview - 如何在默認瀏覽器中打開外部鏈接？

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