2012-04-09 61 views
1

我想讀取一個像JSON文件一樣被格式化的字符串並將其打印在屏幕上。 因此我正在使用GSON-Library。使用gson解析Json文件:MalformedJsonException

每次我想要編譯我得到一個線程異常「主」 com.google.gson.JsonSyntaxException錯誤

我的代碼看起來像這樣

public class Test { 

public static void main(String... args) throws Exception { 
    String json = 
     "{" 
        + "'tag_name' : 'M mit Mbrunnen'," 
        + "'tag_id' : 'de_bw_xx_mstall'," 
        + "'tag_description': 'false'," 
        + "'tag_latitude': '42.704895'," 
        + "'tag_longitude': '10.652187'," 
        + "'tag_description_f_a': 'Ein weiteres Highlight in H'," 
     + "}"; 

    // Now do the magic. 
    Data data = new Gson().fromJson(json, Data.class); 

    // Show it. 
    System.out.println(data); 
} 
} 

class Data { 
private String tag_name; 
private String tag_id; 
private String tag_description; 
private String tag_latitude; 
private String tag_longitude; 
private String tag_descrption_f_a; 

public String getName() { return tag_name; } 
public String getId() { return tag_id; } 
public String getDescription() { return tag_description; } 
public String getLatitude() { return tag_latitude; } 
public String getLongitude() { return tag_longitude; } 
public String getDescriptionVoice() { return tag_descrption_f_a; } 

public void setName(String name)       { this.tag_name = name; } 
public void setId(String id)        { this.tag_id = id; } 
public void setDescription(String description)    { this.tag_description = description; } 
public void setLatitude(String latitude)     { this.tag_latitude = latitude; } 
public void setLongitude(String longitude)     { this.tag_longitude = longitude; } 
public void setDescriptionVoice(String descriptionVoice) { this.tag_descrption_f_a = descriptionVoice; } 

public String toString() { 
    return String.format("%s,%s,%s,%s,%s,%s", tag_name, tag_id, tag_description, tag_latitude, tag_longitude, tag_descrption_f_a); 
} 
} 

我得到的錯誤:

Exception in thread "main" com.google.gson.JsonSyntaxException: com.google.gson.stream.MalformedJsonException: Expected name at line 1 column 221 at com.google.gson.Gson.fromJson(Gson.java:769) at com.google.gson.Gson.fromJson(Gson.java:721) at com.google.gson.Gson.fromJson(Gson.java:670) at com.google.gson.Gson.fromJson(Gson.java:642) at Test.main(Test.java:19) Caused by: com.google.gson.stream.MalformedJsonException: Expected name at line 1 column 221 at com.google.gson.stream.JsonReader.syntaxError(JsonReader.java:1298) at com.google.gson.stream.JsonReader.nextInObject(JsonReader.java:739) at com.google.gson.stream.JsonReader.peek(JsonReader.java:382) at com.google.gson.stream.JsonReader.hasNext(JsonReader.java:349) at com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$Adapter.read(ReflectiveTypeAdapterFactory.java:169) at com.google.gson.Gson.fromJson(Gson.java:755) ... 4 more

所以錯誤發生在這裏:

// Now do the magic. 
    Data data = new Gson().fromJson(json, Data.class); 

我想我的JSON數據提供的格式不正確。

回答

3

我想你的JSON中沒有很好地形成

它應該是這樣的

"{ 
    "tag_name": "M mit Mbrunnen", // always use double quotes, single quote is not a valid json 
    "tag_id": "de_bw_xx_mstall", 
    "tag_description": "false", 
    "tag_latitude": "42.704895", 
    "tag_longitude": "10.652187", 
    "tag_description_f_a": "Ein weiteres Highlight in H" // extra comma removed from here 
}" 

您可以驗證您的JSON這裏http://jsonlint.com/

+2

感謝您有用的答案和驗證頁! 當然,你總是用「而不是」,但因爲JSON實際上是一個字符串,所以'是正確的。 錯誤在這裏: +''tag_description_f_a':'Ein weiteres H' - >< - 「 我剛剛刪除了逗號,現在它工作;) – RCK69 2012-04-09 13:48:31