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public String Encryption(String toEncrypt) throws Exception
{
Security.addProvider(new org.bouncycastle.jce.provider.BouncyCastleProvider());
EditText et = (EditText) findViewById(R.id.entry);
byte[] input = toEncrypt.getBytes();
byte[] keyBytes = "hello".getBytes();
// et.setText("in encryption");
SecretKeySpec key = new SecretKeySpec(keyBytes, "AES");
Cipher cipher = Cipher.getInstance("AES/ECB/PKCS7Padding", "BC");
// et.setText("in encryption");
cipher.init(Cipher.ENCRYPT_MODE, key);
et.setText("in encryption");
byte[] cipherText = new byte[cipher.getOutputSize(input.length)];
int ctLength = cipher.update(input, 0, input.length, cipherText, 0);
ctLength += cipher.doFinal(cipherText, ctLength);
// et.setText("in encryption");
// return "abc";
return cipherText.toString();
從我加粗的代碼行(cipher.init(Cipher.ENCRYPT_MODE, key);
)程序不工作 - 我得到一個異常。這條線有什麼問題?我試圖基本上加密一個字符串,並用這個函數返回它。這個在android中的加密代碼有什麼問題?
嘗試重新格式化,並且還包含異常的內容。否則,真的很難回答你的問題。 – 2011-02-09 23:53:57