如何在JsonParsing中排序時間？

Question

我需要排序從JSON提要時間

{ 
    "events":{ 
     "event":[ 
     { 
     } 
     ] 
    } 
} 

誰能幫我解決這個問題？

Answer 1

我不知道你怎麼想的那樣進行排序和完整數據的樣子，但這裏的想法：

JSONArray jsonEvents = new JSONObject(json).getJSONArray("event"); 
JSONObject [] events = new JSONObject[jsonEvents.length()]; 

// fill an array with your events 
for (int i = 0; jsonEvents.length(); i++) { 
    events[i] = jsonEvents.getJSONObject(i); 
} 

// sort them 
Arrays.sort(events, new Comparator<JSONObject>() { 
    static final SimpleDateFormat sdfToDate = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss"); 

    public int compare(JSONObject event1, JSONObject event2) { 
     return sdfToDate.parse(event1.getString("startTime")).compareTo(
      sdfToDate.parse(event2.getString("startTime")) 
    } 
}); 

Answer 2

String myjson = "{"events":{"event":[{"title":"Audi urban future","startTime":"2011-09-16 00:30:00","endTime":"2011-09-22 00:35:00","description":"test","image":"http://audi.smart-media.no/wp-content/uploads/2011/09/20110919130749-medium.jpg","latitude":45.73154,"longitude":4.8592365}]}}" 

    JSONArray array= new JSONArray(myjson); 

    for(int i = 0; i < array.length; i++) { 
     JSONObject object = (JSONObject) array.get(i); 
     object.getString("startTime"); 
     } 

Answer 3

可以使用

Collections.sort(String,new Comparator<String>() { 

           public int compare(String arg0, String arg1) { 
            // TODO Auto-generated method stub 
            return 0; 
           } 
          }); 

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