我正在使用CGAffineTransformMake來轉換視圖。它旋轉,縮放和翻譯。這工作得很好。但我無法想出一種將比例限制在最大值的方法。限制CGAffineTransform Scale
如果超過規模,我仍然需要應用當前的旋轉和平移。
任何建議,非常感謝!
來源:
UITouch *touch1 = [sortedTouches objectAtIndex:0];
UITouch *touch2 = [sortedTouches objectAtIndex:1];
CGPoint beginPoint1 = *(CGPoint *)CFDictionaryGetValue(touchBeginPoints, touch1);
CGPoint currentPoint1 = [touch1 locationInView:self.superview];
CGPoint beginPoint2 = *(CGPoint *)CFDictionaryGetValue(touchBeginPoints, touch2);
CGPoint currentPoint2 = [touch2 locationInView:self.superview];
double layerX = self.center.x;
double layerY = self.center.y;
double x1 = beginPoint1.x - layerX;
double y1 = beginPoint1.y - layerY;
double x2 = beginPoint2.x - layerX;
double y2 = beginPoint2.y - layerY;
double x3 = currentPoint1.x - layerX;
double y3 = currentPoint1.y - layerY;
double x4 = currentPoint2.x - layerX;
double y4 = currentPoint2.y - layerY;
// Solve the system:
// [a b t1, -b a t2, 0 0 1] * [x1, y1, 1] = [x3, y3, 1]
// [a b t1, -b a t2, 0 0 1] * [x2, y2, 1] = [x4, y4, 1]
double D = (y1-y2)*(y1-y2) + (x1-x2)*(x1-x2);
if (D < 0.1) {
return CGAffineTransformMakeTranslation(x3-x1, y3-y1);
}
double a = (y1-y2)*(y3-y4) + (x1-x2)*(x3-x4);
double b = (y1-y2)*(x3-x4) - (x1-x2)*(y3-y4);
double tx = (y1*x2 - x1*y2)*(y4-y3) - (x1*x2 + y1*y2)*(x3+x4) + x3*(y2*y2 + x2*x2) + x4*(y1*y1 + x1*x1);
double ty = (x1*x2 + y1*y2)*(-y4-y3) + (y1*x2 - x1*y2)*(x3-x4) + y3*(y2*y2 + x2*x2) + y4*(y1*y1 + x1*x1);
return CGAffineTransformMake(a/D, -b/D, b/D, a/D, tx/D, ty/D);
完美!非常感謝!因爲我沒有足夠的聲望,所以我不能投票回答你的答案。有人可以爲我投票嗎?如果可以的話,我會把它投票10次!再次感謝。 – 2011-04-22 04:34:14
順便說一句:我有一個線性代數文本,我試圖通過學習這種東西。 – 2011-04-22 04:34:53
這是完美的,謝謝! – 2011-08-31 08:12:42