插入目錄文件夾中的圖像不在數據庫中？

插入目錄文件夾中的圖像不在數據庫中？請查看代碼，可以在文件夾中查看圖像，但不能在數據庫中查看圖像，而是在命令中插入pc.gif，否則文件名將在命令上執行，但執行其他命令？第一個命令是正確的，爲什麼第二個命令被執行。插入目錄文件夾中的圖像不在數據庫中？

if($action=="insertproject"){ 

    if ($_FILES['logo']['name'] != "") { 

    $imageInfo = getimagesize($_FILES['logo']['tmp_name']); // get image size 
    $width = $imageInfo[0]; // image width 
    $height = $imageInfo[1]; // image height 

    if($height > 2000 || $width > 2000){ 
     echo "<script> alert('Image is to big! Try to resize the picture!') </script>"; 
     exit; 
    } // check size 

    $newimg1 = date("YmdHis").".jpg"; // set name for new image 
    $newimg2 = date("YmdHis").".pdf"; // set name for pdf if is necesary 

    if(stristr($_SERVER['OS'],"win")){ 
     $path = "prodimg/"; 
    } // determin path of image folder 
    elseif(stristr($_SERVER['OS'],"linux")){ 
     $path = str_replace("admin.php","",$_SERVER['SCRIPT_FILENAME']) . "prodimg/"; 
    } 
    else { 
     $path = "prodimg/"; 
    } 

    move_uploaded_file ($_FILES['logo']['tmp_name'], $path . $newimg1 ); 
    } // copy image in image folder 

    else{ 
    $newimg1="pc.gif"; 
    } // if is not posible than set image name as pc.gif 

    $serviceid = $_POST['serviceid']; 
    $projectcode = $_POST['projectcode']; 
    $projecttitle = $_POST['projecttitle']; 
    $update = $_POST['update']; 
    $projectstatus = $_POST['projectstatus']; 
    $progress = "on progress"; 
    $sector = $_POST['sector']; 

    $dateofrtecreview = $_POST['dateofrtecreview']; 
    $dateapprovedatrpmolevel = $_POST['dateapprovedatrpmolevel']; 
    $dateendorsedtonpmo = $_POST['dateendorsedtonpmo']; 
    $dateapprovednpmo = $_POST['dateapprovednpmo']; 
    $datereceivedbyrpmo = $_POST['datereceivedbyrpmo']; 
    $expectedoutput = $_POST['expectedoutput']; 
    $yearassistancereceived = $_POST['yearassistancereceived']; 
    $setupinvestment = $_POST['setupinvestment']; 
    $beneficiaryinvestment = $_POST['beneficiaryinvestment']; 
    $projectdescription = $_POST['projectdescription']; 

    $res = mysql_query("insert into  appointment_detail(`serviceid`,`picture`,`projectdescription`,`dateofrtecreview`,`dateapprovedatrpmol evel`,`dateendorsedtonpmo`,`dateapprovednpmo`,`datereceivedbyrpmo`,`expectedoutput`,`projectcode`,`projecttitle`,`update`,`status`,`projectstatus`,`sector`,`setupinvestment`,`beneficiaryinvestment`) 
     values('$serviceid','$newimg1','$projectdescription','$dateofrtecreview','$dateapprovedatrpmolevel',' $dateendorsedtonpmo','$dateapprovednpmo','$datereceivedbyrpmo','$expectedoutput','$projectcode','$pro jecttitle','$update','$progress','$projectstatus','$sector','$setupinvestment','$beneficiaryinvestmen t')"); 

    echo "<script>location.replace('admin.php?action=showallprojects')</script>"; 
    }

來源

2014-10-01 Glendon Philipp Baculio

展望這裏有明顯的答案......'$ _FILES ['logo'] ['name'] ==「」' – Bryan 2014-10-01 02:49:29

''$ beneficiary投資'）「）'你在那裏有空間應該是''$ beneficiaryinvestment'）」） – 2014-10-01 02:49:48

@Bryan你是什麼意思？ – 2014-10-01 02:55:54

您的查詢應該是這樣的閱讀代碼中的註釋，並使用庫MySQLi或PDO

$res = mysql_query("insert into  appointment_detail 
     (`serviceid`,`picture`,`projectdescription`,`dateofrtecreview`,`dateapprovedatrpmolevel`, 
     `dateendorsedtonpmo`,`dateapprovednpmo`,`datereceivedbyrpmo`,`expectedoutput`, 
     `projectcode`,`projecttitle`,`update`,`status`,`projectstatus`,`sector`,`setupinvestment`, 
     `beneficiaryinvestment`) 
     values('$serviceid','$newimg1','$projectdescription','$dateofrtecreview', 
      '$dateapprovedatrpmolevel',' $dateendorsedtonpmo','$dateapprovednpmo', 
      '$datereceivedbyrpmo','$expectedoutput','$projectcode', 
      '$projecttitle','$update','$progress','$projectstatus','$sector', 
      '$setupinvestment','$beneficiaryinvestment')");

這些都是你的錯誤

'$beneficiaryinvestmen t this should be $'$beneficiaryinvestment 

    //$pro jecttitle' this should be this $projecttitle' 
    //dateapprovedatrpmol evel this should be this dateapprovedatrpmolevel

來源

2014-10-01 03:04:24

插入目錄文件夾中的圖像不在數據庫中？

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