這個C代碼爲什麼給我一個seg錯誤？

Question

可能重複：
How to copy char *str to char c[] in C?

char *token = "some random string"; 
char c[80]; 
strncpy(c, token, sizeof c - 1); 
c[79] = '\0'; 
char *broken = strtok(c, "#"); 

Answer 1

您的代碼不會在下面的崩潰對我來說：

#include <string.h> 

main() 
{ 
char *token = "some random string"; 
char c[80]; 
strcpy(c, token); 
strncpy(c, token, sizeof c - 1); 
c[79] = '\0'; 
char *broken = strtok(c, "#"); 
} 

Answer 2

此代碼的工作，已經指定了正確的包括？

#include <string.h> /* 
#include <stdio.h> 
#include <stdlib.h> 

int 
main() { 
    /* ORIGINAL CODE */ 
    char *token = "some random string"; 
    char c[80]; 
    strcpy(c, token); 
    strncpy(c, token, sizeof c - 1); 
    c[79] = '\0'; 
    char *broken = strtok(c, "#"); 

    /* ADDED THE FOLLOWING LINES */ 
    printf("%s\n", broken); 
    exit(1); 
}