如何從AJAX響應中檢索JSON變量

Question

當我嘗試從JSON響應中獲取值時，我彈了起來。這裏是我的代碼

代碼：

$.ajax({ 
    url: 'checkvotes.php', 
    dataType: "json", 
    success: function(data) { 
    // want to fetch UP and DOWN variables from JSON here 
    } 
}); 

AJAX從PHP

{"sample":[{"id":"1","message":"my message","up":"200","down":"34"}]} 

Answer 1

$.ajax({ 
    url: 'checkvotes.php', 
    dataType: "json", 
    success: function(data) { 
     var up = data.sample[0].up; 
     var down = data.sample[0].down; 
    } 
}); 

Answer 2

var up = data['sample'][0]['up'], 
    down = data['sample'][0]['down'] 

剛剛打印的console.log（數據）檢查您的JSON響應

Answer 3

嘗試data.sample[0].up和data.sample[0].down。如果有疑問，可以使用這個JavaScript來模擬電話：

var data = {"sample":[{"id":"1","message":"my message","up":"200","down":"34"}]}; 

運行在一個調試器和檢查data。