我想使用異步並等待,而我的問題是它不會等待後臺進程完成。也許你想知道爲什麼我不能同步運行應用程序? 我想盡快完成我的任務的一部分,其餘的可以等待,如本例中所示。 謝謝你們的幫助! =)如何知道使用異步時Task或Void方法是否仍在運行
class Program
{
static void Main(string[] args)
{
Run();
//Problem or Maybe Not? Needs this
//So that my application won't close immediately
Console.ReadLine();
}
private async static void Run()
{
Task<bool> TBool = ProcessRecords();
if (await TBool)
{
//Problem #1 This Line Doesn't Show
Console.WriteLine("End of Code");
//SHould be safe to close the application by Now
//But goes through here not waiting for the return
//of the last process.
Environment.Exit(0);
//My temporary solution is to indicate a Task.Delay(80000)
//to make sure that all the logging in the background
//are all done. I dont know if there is a function that shows
//that there are task running on the background or any
//other workaroung will help. =) thanks
}
}
private async static Task<bool> ProcessRecords()
{
Task newTask = null;
//Loop through all the records and send
//all the records to MQ ASAP
for (int x = 0; x < 10; x++)
{
//I wont wait for this Task so
//I can send the next record
newTask = SendToMQ(x);
}
//I only need to wait for the last Task to
//indicate that I can exit the system
//as soon as it finish
//Problem #2 The Console.WriteLine doesnt show the last record.
await newTask;
return true;
}
private async static Task SendToMQ(int count)
{
//actual sending of message (Important)
await Task.Delay(1000);
//Process of Logging Connect to DB etc, (Not so Important, but takes most of the time)
await LoggingRecord();
Console.Clear();
Console.WriteLine("Done Processing " + count.ToString() + " records");
}
//Logging of each record
private async static Task LoggingRecord()
{
await Task.Delay(5000);
//Problem #3 This Line Doesn't Show
Console.WriteLine("Last Log Finished");
}
}
你能不能設置一些布爾標誌或分配和檢查某些屬性..?當你通過代碼的時候會發生什麼,最後的日誌完成寫入控制檯主窗口..? – MethodMan
我編輯了你的標題。請參閱:「[應該在其標題中包含」標籤「](http://meta.stackexchange.com/questions/19190/)」,其中的共識是「不,他們不應該」。 –
顯然Logging沒有完成他的事情,但應用程序強制關閉整個應用程序,即使Logging尚未完成寫入,這就是爲什麼我給我的應用程序Task.Delay(8000)等待它登錄,但這不僅僅是好的編碼,也不是動態的。感謝所有的幫助=) –