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我有一個CodeIgniter庫。當我從我的控制器訪問它時,會生成嚴重性:Notice的PHP錯誤。但是,調試器顯示超級對象存在於庫中,並且是超級對象。CodeIgniter庫:訪問CodeIgniter Superobject導致PHP錯誤的嚴重性:通知
這裏是圖書館類:
class Auth_lib {
protected $CI;
public function __construct()
{
$this->$CI =& get_instance();
$this->$CI->load->model('auth_model');
$this->$CI->load->library('session');
}
/**
* checks if the current user is logged into a session
* @param
* @return boolean
*/
public function is_logged_in(){
$result = $this->$CI->session->userdata('is_logged_in');
return $result;
}
}
這是怎樣的庫是從我的控制器稱爲:
public function __construct()
{
parent::__construct();
$this->load->helper('url_helper');
$this->load->library('auth_lib');
// test if user is logged in and authorised, if not redirect to login controller
if($this->auth_lib->is_logged_in() != null){
// check if is admin
}
} else {
// not logged in, redirect to login controller
}
}
那麼,爲什麼我收到此錯誤:
A PHP Error was encountered Severity: Notice Message: Undefined variable: CI Filename: libraries/Auth_lib.php Line Number: 20
嘗試'$這個 - 的> CI'代替'$此 - > $ CI' – MonkeyZeus
如果如果你使用'$ this - > $ CI =&get_instance();'然後在使用'$ CI'之前,你必須聲明'$ CI ='CI';' – MonkeyZeus
你有一個額外的括號後//檢查是否是admin – Callombert