2011-05-16 107 views
-2

可能重複:
Cross thread problem?交叉線程問題? C#

我有一個問題,當我把這個線程。 我的想法是當你選擇文件夾郵件 - 當Func1完成時做Func1是MessageCollections() 然後下載郵件文件夾 - Func2是SaveMail() 當下載完成一個郵件然後添加項目到列表視圖 - Func3是AddMesToMailList() 但我的代碼有問題,你能幫助我嗎? 錯誤是:跨線程線MailTree.SelectedNode.Text

private delegate void SaveMailDelegate(); 
      private void AddMesToMailList(IAsyncResult ia) 
      { 
        ListViewItem item = new ListViewItem(); 
        Mime m = EncodingMail(MailTree.SelectedNode.Text, mes); 
        item.Text = mes.MessageUid.ToString(); 
        item.SubItems.Add(m.MainEntity.Subject); 
        ReturnMime(m); 
        if (mailfromname != null) 
         item.SubItems.Add(mailfromname); 
        else item.SubItems.Add(mailfrom); 
        item.SubItems.Add(m.MainEntity.Date.ToString()); 
        item.SubItems.Add(mailfrom); 
        MailList.Items.Add(item);   
      } 
      private delegate ImapX.MessageCollection SelectMailFolder(string foldername); 
      ImapX.MessageCollection MessageCollections(string foldername) 
      { 
       return messages=client.Folders[foldername].Search("ALL", false); 
      } 
    public void SaveMail() 
      { 
       string path1= "D:\\" ; 
       string path2=Username; 
       string path3=MailTree.SelectedNode.Text; 
       string path4 = mes.MessageUid.ToString() + ".eml"; 
       // @"D:\" + Username + "\\" + MailTree.SelectedNode.Text + "\\" + mes.MessageUid.ToString() + ".eml")\ 
       string path=Path.Combine(path1,path2,path3,path4); 
       string savepath = Path.Combine(path1, path2, path3); 
       if (!File.Exists(path)) 
       { 
        mes.Process(); 
        mes.SaveAsEmlToFile(savepath, mes.MessageUid.ToString()); //Store messages to a Location 
       } 
      } 


    private void MailTree_AfterSelect(object sender, System.Windows.Forms.TreeViewEventArgs e) 
       { 
           MailList.Items.Clear(); 
           for (int i = 0; i < client.Folders.Count; i++) 
           {       
            (ContextMenuListView.Items[1] as ToolStripMenuItem).DropDownItems[i].Click += new EventHandler(MainForm_Click); 
           } 
           if (MailTree.SelectedNode.Text == Username) 
           { 
            webBrowser1.Visible = false;//webBrowser1.DocumentText = "Hello Baby"; 
            AttachmentList.Visible = false; 
            groupBox1.Visible = false; 
           } 
           else 
           { 
            webBrowser1.Visible = true; 
            groupBox1.Visible = true; 
            string select = MailTree.SelectedNode.Text;       
            //messages = client.Folders[select].Search("ALL", false);// Search mail in your choossen Folder 
            SelectMailFolder se = null; 
            se += new SelectMailFolder(MessageCollections); 
            se.BeginInvoke(select,new AsyncCallback(NewMethod), null);       

           } 
       } 

       private void NewMethod(IAsyncResult ias) 
       { 
        AmoutOfMail = messages.Count(); //Amout of Mail in this Folder           
        for (int i = 0; i < AmoutOfMail; i++) 
        { 
         mes = messages[i]; 
         SaveMailDelegate del = null; 
         del += new SaveMailDelegate(SaveMail); 
         IAsyncResult ia = del.BeginInvoke(new AsyncCallback(AddMesToMailList), null); 
        } 
       } 
+6

「但蹊蹺的在我的代碼」:這是一件好事,說明你認爲什麼是錯的/你爲什麼認爲這是錯誤/你得到任何錯誤。 – forsvarir 2011-05-16 10:24:40

+0

有什麼不對...? ,地球上的任何人如何知道你面臨的問題是什麼?陳述問題 – TalentTuner 2011-05-16 10:27:02

+0

@forsvarir:因爲有錯誤的交叉線程: – giaosudau 2011-05-16 10:28:05

回答

2

從我狂野的猜測,你可能會得到跨線程控制訪問萬阿英,蔣達清,當你從另一個線程碰任何UI控件occures除主UI線程外

+0

是的,這是我的問題:( – giaosudau 2011-05-16 10:30:19

4

您正在調用單獨線程中的AddMesToMailList。你不能與另一個線程中的Gui元素進行交互。使用調用切換到GUI線程

this.Invoke(new Action(AddMesToMailList))

+0

有一個相同的錯誤:( – giaosudau 2011-05-16 10:37:15