2012-11-17 91 views
0

我有類似:MPI_Waitsome分段錯誤?

int numprocs, id, arr[10], winner = -1; 
bool stop = false; 
MPI_Request reqs[10], winnerNotification; 

MPI_Init(NULL, NULL); 
MPI_Comm_size(MPI_COMM_WORLD, &numprocs); 
MPI_Comm_rank(MPI_COMM_WORLD, &id); 

srand(time(NULL) + id); 

if (id == 10) { 
    int completed = 0; 
    int* completedIndexes; 
    for (int i = 0; i < 10; i++) { 
     MPI_Irecv(&arr[i], 1, MPI_INT, i, 0, MPI_COMM_WORLD, &reqs[i]); 
    } 
    MPI_Waitsome(10, reqs, &completed, completedIndexes, MPI_STATUSES_IGNORE); 
    cout << completed << " seems to have completed" << endl; 
    for (int i = 0; i < completed; i++) { 
     cout << completedIndexes[i] << " have completed!"; 
    } 
} 

while (id < 10 && winner == -1) { 
    if (((rand() % 100) + 1) < 5) { // players have 5% chance of completing 
     MPI_Send(&id, 1, MPI_INT, 10, 0, MPI_COMM_WORLD); 
     cout << id << " completed" << endl; 
     MPI_Wait(&winnerNotification, MPI_STATUS_IGNORE); 
    } 
} 

MPI_Finalize(); 

這是給分段錯誤,我認爲它是與Waitsome?但是什麼?錯誤的樣子:

1 completed 
[JM:01317] *** Process received signal *** 
[JM:01317] Signal: Segmentation fault (11) 
[JM:01317] Signal code: Address not mapped (1) 
[JM:01317] Failing at address: 0x646574 
4 completed 
5 completed 
[JM:01320] *** Process received signal *** 
[JM:01320] Signal: Segmentation fault (11) 
[JM:01320] Signal code: Address not mapped (1) 
[JM:01320] Failing at address: 0x646574 
3 completed 
[JM:01319] *** Process received signal *** 
[JM:01319] Signal: Segmentation fault (11) 
[JM:01319] Signal code: Address not mapped (1) 
[JM:01319] Failing at address: 0x646574 
... 

回答

1

MPI_Waitsome預計整數數組,它存儲的完成的請求的指標,但你給它的是一個未初始化的int指針。鑑於您已將10硬編碼爲請求數,請使用以下代碼:

if (id == 10) { 
    int completed = 0; 
    int completedIndexes[10]; 
    for (int i = 0; i < 10; i++) { 
     MPI_Irecv(&arr[i], 1, MPI_INT, i, 0, MPI_COMM_WORLD, &reqs[i]); 
    } 
    MPI_Waitsome(10, reqs, &completed, completedIndexes, MPI_STATUSES_IGNORE); 
    cout << completed << " seems to have completed" << endl; 
    for (int i = 0; i < completed; i++) { 
     cout << completedIndexes[i] << " have completed!"; 
    } 
} 
+0

看來最大完成值爲1?我猜測它是因爲一旦第一個進程發送,它會導致等待返回? –

+0

不,這是由於在Open MPI中實現了進程(帶來一個未完成的非阻塞請求)的方式。如果您啓用了進程線程編譯Open MPI,則可以在後臺獲取請求。但這樣做會影響某些操作的延遲。如果您想等待所有接收完成,請使用'MPI_WAITALL'。 –

+0

嗯問題是,並非所有的進程可能完成。我只想捕獲同時完成的過程(大致至少) –