如何顯示將取決於用戶想要的數組？

Question

這是1種方法。

public static void main(String[] Ropher)throws IOException{ 
    BufferedReader br = new BufferedReader (new InputStreamReader (System.in)); 

    String[] Accommodation = {"", "Standard Room", "Double Room", "Matrimonial Room", "Triple Room"}; // Accommodation 
    int SwitchOne, SwitchTwo; 
    int Option;//Options 

    /*----------------------------------------------------------------- 
    * Costumer's Information 
    -----------------------------------------------------------------*/ 
    do{//Start Of First Loop - Customer's Info 
    System.out.print("\nEnter Number Of Records : "); 
    int Records = Integer.parseInt(br.readLine()); 
    String [][] Fullname = new String [Records][100]; 
    int [] Night = new int[100]; 
    int [] Guest = new int[100]; 
    int[] Confirm = new int [100]; 
    for (int x = 0; x < Records; x++){// Start For Records 

    System.out.print("\nConfimation Number: "); 
    Confirm[x] = Integer.parseInt(br.readLine()); 
    System.out.print("\nFirst Name: "); 
    Fullname[x][0] = br.readLine(); 
    System.out.print("Last Name: "); 
    Fullname[x][1] = br.readLine(); 
    System.out.print("Guest: "); 
    Guest[x] = Integer.parseInt(br.readLine()); 
    System.out.print("Night: "); 
    Night[x] = Integer.parseInt(br.readLine()); 
    System.out.println(); 

    do{// Start Of Second - Main Menu 

     System.out.print("\n        ||Main Menu||\n\n"); 
     System.out.print("|=====================================================================|"); 
     System.out.print("\n ************************  Bed Types  ************************\n"); 
     System.out.print("|=====================================================================|\n\n"); 
     System.out.print("1. Standard..............................................P500.00\n"); 
     System.out.print("2. Double................................................P800.00\n"); 
     System.out.print("3. Matrimonial...........................................P1,240.00\n"); 
     System.out.print("4. Triple................................................P1,500.00 \n"); 
     System.out.print("5. Exit\n"); 
     System.out.println("\n (WIfi, air conditioned room, LED TV, FREE BREAKFAST)"); 
     System.out.println("\t *Except Standard rooms and Double rooms");  

     System.out.print("\n\nPlease Select Room Type: "); 
     SwitchOne = Integer.parseInt(br.readLine()); 

     //Start of Switch for SwitchOne - First Switch 


    if ((x + 1 - Records) == 0){ 

    System.out.print("\n\nList Of Customers:"); 

    for (x = 0; x < Records; x++){ 

     System.out.print("\n|---------------------------------------------------------------------|\n"); 
     System.out.print("\n\nConfirmation Number:  |---------------> " + Confirm[x]); 
     System.out.print("\nGuest Name:     |---------------> " + Fullname [x][0] + " " + Fullname [x][1]); 
     System.out.print("\nNumber Of Guest:   |---------------> " + Guest [x]); 
     System.out.print("\nNumber Of Nights:   |---------------> " + Night[x]); 

這只是一個選項，我只是不知道什麼價值放在住宿。

System.out.println（「\ nAccommodations：| --------------->」+ Accommodation [SwitchOne]）;

  } 

    }else{ 
      continue; 
     } 

    }// End For Records 

    }while (First);//End Of First Loop - Customer's Info 


}//IO 
}//Body 

我的計劃是所有關於酒店信息和計費系統。

如果有2位顧客想要辦理登機手續並且他們選擇不同的房間，並且當我檢查客戶名單時，他們房間的輸出是相同的。

而且我知道，這個問題是

System.out.println("\nAccommodations:    |---------------> " + Accommodation[SwitchOne]); 

我會做什麼，以固定的呢？

請幫我解決這個問題。

Answer 1

您正在使用SwitchOne來了解所選的準確度。所以如果記錄是2或更多，則最後一條記錄將改變SwitchOne的值。

所以當你打印所有的細節時，對於所有的SwitchOne將會是一樣的。

避免爲selectedAccomadation []創建一個新的數組並從那裏獲取它。 這樣

int[] Confirm = new int [100]; 
String[] selectedAccomadation = new String[100]; 
... 
System.out.print("\n\nPlease Select Room Type: "); 
selectedAccomadation[x] = br.readLine(); 

而且在for循環得到這樣

System.out.println("\nAccommodations: |---------------> " + selectedAccomadation[x]); 

請通知我，如果我錯了。