如何從JSON調用NSString到UIAlertView？

Question

我想從json傳遞一些值給UIAlertView的消息。我有一些代碼

- (void)jsonParse{ 

    NSString* path = @"http://phdprototype.tk/getResultData.php"; 
    NSURL* url = [NSURL URLWithString:path]; 
    NSString* jsonString = [[NSString alloc]initWithContentsOfURL:url encoding:NSUTF8StringEncoding error:nil]; 
    NSData* jsonData = [jsonString dataUsingEncoding:NSUTF8StringEncoding]; 
    NSDictionary* dic = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingMutableLeaves error:nil]; 

    NSDictionary* resultDic = [dic objectForKey:@"maxid"]; 
    NSString* recData = [resultDic objectForKey:@"recommendData"]; 
    NSString* rData = [resultDic objectForKey:@"room"]; 
    NSString* lData = [resultDic objectForKey:@"level"]; 

} 

- (void)locationView 
{ 
    UIAlertView *alert = [[UIAlertView alloc] initWithTitle: @"Recommendation" 
                message:[NSString stringWithFormat:@"OK! There is another collection which located at room %@ in level %@."] 
                delegate: self 
              cancelButtonTitle: nil 
              otherButtonTitles: @"GO", nil]; 

    [alert show]; 
} 

據我所知，我必須做一些
message:[NSString stringWithFormat:@"OK! There is another collection which located at room %@ in level %@."]。但是，我不知道該怎麼做。有人能告訴我如何將lData和rData的值傳遞給uialertview的消息嗎？

Answer 1

，您可以撥打全球NSString變量定義你的消息

在.h文件

NSString *message; 

在jsonParse方法

- (void)jsonParse { 
    //Your Stuff 
    message = [NSString stringWithFormat:@"OK! There is another collection which located at room %@ in level %@", lData, rData]; 
} 

，然後在UIAlertView

UIAlertView *alert = [[UIAlertView alloc]  initWithTitle:@"Recommendation" 
                message:message 
                delegate:self 
              cancelButtonTitle:nil 
              otherButtonTitles:@"GO", nil]; 

[alert show]; 

Answer 2

其實很簡單。你正在做的事情只是少數缺失的事情。

1. 聲明rData & lData爲屬性在你的類，

   @interface <classname> 
   @propert (nonatomic,strong) NSString *lData; 
   @propert (nonatomic,strong) NSString *rData; 
   @end 
   

2. 然後你的字符串可以使用形成

   [NSString stringWithFormat:@"OK! There is another collection which located at room %@ in level %@.", lData, rData]; 
   

這應該解決您的問題。

Answer 3

UIAlertView *alert = [[UIAlertView alloc] initWithTitle: @"Recommendation" 
               message:[NSString stringWithFormat:@"OK! There is another collection which located at room %@ in level %@.", iData, rData] 
               delegate: self 
             cancelButtonTitle: nil 
             otherButtonTitles: @"GO", nil]; 

你寫的論據stringWithFormat後，只要寫的值。參數的數量應該與參數字符串中使用的%@s的數量相匹配，並且您的參數應該用逗號分隔，否則您將收到構建錯誤。

Answer 4

同時聲明變量（RDATA & LDATA）全球（手段，在你的界面），然後使用它像這樣

UIAlertView *alert = [[UIAlertView alloc] initWithTitle: @"Recommendation" 
                message:[NSString stringWithFormat:@"OK! There is another collection which located at room %@ in level %@.",lData,rData] 
                delegate: self 
              cancelButtonTitle: nil 
              otherButtonTitles: @"GO", nil]; 

Answer 5

- (void)jsonParse{ 

    //your code 
    [self locationViewWithRoom:rData level:lData]; 

} 

- (void)locationViewWithRoom:(NSString *)room level:(NSString *)level 
{ 
    UIAlertView *alert = [[UIAlertView alloc] initWithTitle: @"Recommendation" 
                message:[NSString stringWithFormat:@"OK! There is another collection which located at room %@ in level %@.", room, level] 
                delegate: self 
              cancelButtonTitle: nil 
              otherButtonTitles: @"GO", nil]; 

    [alert show]; 
}