多個Ajax表單數據上傳jquery

我想上傳多個文件到一個文件夾，這是工作，因爲我在日誌中收到錯誤：「所需的MultipartFile參數'文件'不存在」。請參閱我的下面的代碼，並指示我哪裏出錯。多個Ajax表單數據上傳jquery

<input type="file" id = 'attachmentFileUploadInput' multiple style="display: none;" > 

    function makeProgress(number){ 
     var url = getRelativeURL("web/fileUpload");   
     var formData = new FormData(); 
     formData.append('number', number); 
     fls = document.getElementById("attachmentFileUploadInput").files; //length of files... 
     for(j=0;j<fls.length;j++){ 
      formData.append('files[]', fls[j]); //note files[] not files 
     } 
     // this wroked for single file upload -formData.append('file', $('input[type=file]')[0].files[0]); 
     console.log("form data " + formData); 
     $.ajax({ 
      url : url, 
      data : formData, 
      processData : false, 
      contentType : false, 
      type : 'POST', 
      success : function(data) { 
      FileUploadVisible(true); 
      $('#attachmentModal').modal('hide') 
      $(':input','#attachmentModal').val(""); 
      $("#pbarmain").hide(); 
      $("#pbar").hide(); 
      $("#actionPlanDiv").hide(); 
      setObjectEnabled('#Upload',false); 
      }, 
      error : function(err) { 
       FileUploadErrorVisible(true); 
      } 
    }); 

     }

服務器端：

private static String UPLOADED_FOLDER = "C://temp//"; 

@RequestMapping(value = { "/fileUpload" }, method = RequestMethod.POST) 
@ResponseBody 
public String uploadFile(@RequestParam("number") String number, @RequestParam("file") MultipartFile file, MultipartHttpServletRequest req, HttpServletResponse res) 
{  
    try { 
     File directory = new File(UPLOADED_FOLDER + number); 
       if (! directory.exists()){ 
        directory.mkdir(); 
        } 
      byte[] bytes = file.getBytes(); 
      Path path = Paths.get(UPLOADED_FOLDER + number + "//" + file.getOriginalFilename()); 
      Files.write(path, bytes); 
      logger.info("You have successfully uploaded '" + file.getOriginalFilename() + "'"); 
      return("File Uploaded"); 


    } catch (Exception e) { 
     res.setStatus(HttpServletResponse.SC_INTERNAL_SERVER_ERROR); 
     logger.error("Failed to upload file '" + file.getOriginalFilename() + "'", e); 
     return("File Not Uploaded"); 
    } 
} 

}

來源

2017-04-13 RA19

你用'文件附加文件名[]'，但在服務器端的期望與名'file'如：' @RequestParam（「文件」）MultipartFile文件' –

如何更新服務器端以期望文件[]，我需要更新我的代碼？ – RA19

您是否找到您的解決方案？ –

contentType: 'multipart/form-data'這就是你缺少

來源

2017-04-13 13:07:39

錯誤：原因：org.apache.commons.fileupload.FileUploadException：請求被拒絕，因爲沒有找到多部分邊界 – RA19

多個Ajax表單數據上傳jquery

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